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Misha Larkins [42]
3 years ago
14

Pls help due in 10 mins

Mathematics
2 answers:
gregori [183]3 years ago
5 0

Answer:

the answer is 5

Step-by-step explanation:

hope that helps

slavikrds [6]3 years ago
4 0
The slope is + 1.5. if the line continues at this constant rate, the answer ends up being 16 i’m pretty sure
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Please help me with this math problem
Alex_Xolod [135]

Answer:

x-intercept(s):  

(−8,0)

y-intercept(s):  

(0,6)

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP ME!
sattari [20]

You want to know how long it'll take for the bacteria to grow
to (800/500) = 1.6 times their initial population.

The number of double-times it'll take is 

                         [ log(1.6) / (log(2) ]  =  0.6781 .

The double-time for these particular critters is 12 hours,
so it'll take them

                             0.6781  x  12 hours  =  8.137 hours

                                                                =  8 hours  8.2 minutes .
3 0
3 years ago
Can someone help me please
goldenfox [79]

Answer:

1. \quad\dfrac{1}{k^{\frac{2}{3}}}\\\\2. \quad\sqrt[7]{x^5}\\\\3. \quad\dfrac{1}{\sqrt[5]{y^2}}

Step-by-step explanation:

The applicable rule is ...

  x^{\frac{m}{n}}=\sqrt[n]{x^m}

It works both ways, going from radicals to frational exponents and vice versa.

The particular power or root involved can be in either the numerator or the denominator. The transformation applies to the portion of the expression that is the power or root.

7 0
4 years ago
Please answer correctly !!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!
boyakko [2]

Answer:

49

Step-by-step explanation:

y = 7^2

= 49

5 0
3 years ago
Completely factor the given expression over the integers.<br><br> (Correct gets brainliest)
elena-14-01-66 [18.8K]

Answer:

50

Step-by-step explanation:

would it be 50 because you the q to the power of 2 is 2q. Then you would subtract to the other side of the equation so it would be -100=-2q. After you would divided the -2 in -2q on both sides and -100/-2 is 50. So your answer is q=50

7 0
3 years ago
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