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3 years ago

Which recursive rule best describes the sequence 3, 14, 36, 80, ...

Mathematics

1 answer:

Naddika [18.5K]3 years ago

8 0

Answer c -step explanation:

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What is the area of the figure?

8_murik_8 [283]

Area of the square is 30 . area of the triangle is 6 . so 36

3 0

3 years ago

Mark invests $8,008 in a retirement account with a fixed annual interest rate of 2% compounded 6 times per year. What will the a

love history [14]

Given:

Principal value = $8,008

Rate of interest = 2% compounded 6 times per year.

Time = 16 years

To find:

The account balance after 16 years.

Solution:

The formula for amount is:

$A=P\left(1+\dfrac{r}{n}\right)^{nt}$

Where, P is principal, r is the rate of interest, n is the number of times interest compounded in an year and t is the number of years.

Putting $P=8,008, r=0.02,n=6,t=16$ in the above formula, we get

$A=8008\left(1+\dfrac{0.02}{6}\right)^{6(16)}$

$A=8008\left(\dfrac{6.02}{6}\right)^{96}$

$A=11022.1721148$

$A\approx 11022.17$

Therefore, the account balance after 16 years is $11022.17.

4 0

3 years ago

Write an expression that, when simplified, is equivalent to 15x + 7

Bas_tet [7]

15 times x plus 7
I hope i helped!

8 0

4 years ago

What is the common difference in this sequence 4,13,22,31,40<br>A) 9<br>B) 1/9<br>C) 11<br>D) 10

tatiyna

Answer:

The common difference is (a.): 9, as you add 9 in order to get to the next number in the sequence each time.

+if this helped you, please consider marking it the Brainliest. thank you.

5 0

3 years ago

.. Which of the following are the coordinates of the vertices of the following square with sides of length a?

atroni [7]

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Step-by-step explanation:

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

To find the sides of a square, let us use the distance formula,

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } S T=\sqrt{(a-0)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } T W=\sqrt{(a-a)^{2}+(0-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,a), T(a,a), W(a,0)$ has sides of length a.

Option B: $O(0,0), S(0,a), T(2a,2a), W(a,0)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

This is not a square because the lengths are not equal.

Option C: $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$ has sides of length 2a.

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length OS }=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } S T=\sqrt{(a-a)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } T W=\sqrt{(0-a)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } O W=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

Thus, the square with vertices $O(0,0), S(a,0), T(a,a), W(0,a)$ has sides of length a.

Thus, the correct answers are option a and option d.

8 0

3 years ago