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Ket [755]
2 years ago
10

A rope 10 feet long is cut into two pieces. One piece is used to form a circle and the other used to form a square. Find a funct

ion representing the area of both square and circle as a function of the length of one side of the square.
Mathematics
1 answer:
Brilliant_brown [7]2 years ago
8 0
10-x=C=2πr

(10-x)/(2π)=r

A=π(100-20x+x^2)/(4π^2)

A=(x^2-20x+100)/(4π)

...

x/4=s, x=4s  using this in the area of a circle we get:

A=(16s^2-80s+100)/(4π)

A=(4s^2-20s+25)/π

And of course the area of a square is s^2

A=(4s^2+πs^2-20s+25)/π
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slega [8]

Answer:

18550cm²

Step-by-step explanation:

140×110=15400

½×70×90=3150

15400+3150=18550

5 0
2 years ago
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The population of Philadelphia in 1990 was 1,585,577. In 2010 the population was 1,526,006. What is the percent change the popul
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Answer:

-3.9% I.e there is decrease in the population

Step-by-step explanation:

Population @ 1990 = 1585577

Population @ 2010 = 1526006

% change =

(1526006-1585577)/1526006 × 100%

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7 0
2 years ago
Is this function one-to-one? Explain how you determine your answer
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A function for which every element of the range of the function corresponds to exactly one element of the domain. One-to-one is often written 1-1. Note: y = f(x) is a function if it passes the vertical line test.
7 0
3 years ago
Solve for m 1/C+1/m=1/z
9966 [12]
Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

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4 0
2 years ago
Which statement describes the function y = axn when a = 1 and n is odd?
kiruha [24]

Answer:

The graph is symmetric about the origin.

The graph does not pass through the origin.

Step-by-step explanation:

We're given:

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Because a = 1, then the given function can be rewritten as y = n.

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The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.

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This is true, given the graph is a horizontal line.

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This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.

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2 years ago
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