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Ket [755]
3 years ago
10

A rope 10 feet long is cut into two pieces. One piece is used to form a circle and the other used to form a square. Find a funct

ion representing the area of both square and circle as a function of the length of one side of the square.
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0
10-x=C=2πr

(10-x)/(2π)=r

A=π(100-20x+x^2)/(4π^2)

A=(x^2-20x+100)/(4π)

...

x/4=s, x=4s  using this in the area of a circle we get:

A=(16s^2-80s+100)/(4π)

A=(4s^2-20s+25)/π

And of course the area of a square is s^2

A=(4s^2+πs^2-20s+25)/π
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Normal Distribution

Step-by-step explanation: A normal distribution will generally have a bell shape. It is also called a bell curve, due to its bell shape.

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Luis earns a base salary of $150.00 every week with an additional 14% commission on everything he sells. If Luis sold $6,050.00
max2010maxim [7]
Luis earns a solid $150 and that doesn't change, now you need to calculate 14% of $6,050. 
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3 0
3 years ago
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Find the length of FV
Anna [14]

Answer:

72.47

Step-by-step explanation:

FV cos 43 = TV

FV (0.73135370161 ) = 53

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6 0
3 years ago
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Lines LaTeX: CEC E and LaTeX: ADA D intersect at LaTeX: BB.
Goshia [24]

Answer:

✔️The measure of angle <CBA is equal to the measure of angle <DBE.

✔️The measure of angle CBD is equal to the measure of angle ABE.

✔️The sum of the measures of angles CBD and CBA is 180 degrees.

Step-by-step explanation:

Vertical angles are formed when two straight lines intersect each other at a certain point. The diagram given is a typical example. This, vertical opposite angles formed are said to be congruent, that is their measures are equal to each other.

The following statements are true of the given diagram:

✔️The measure of angle <CBA is equal to the measure of angle <DBE.

(<CBA and ,<DBE are vertically opposite angles)

✔️The measure of angle CBD is equal to the measure of angle ABE.

(They are both vertically opposite angles)

✔️The sum of the measures of angles CBD and CBA is 180 degrees.

(<CBA and <CBD are supplementary angles)

3 0
3 years ago
Write the equation of a Line that is perpendicular to y=5/2x+3 and passes
koban [17]

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\

        m_{2}= -1 ÷ m_{1}

               = -1*\frac{2}{5}=\frac{-2}{5}

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

                                                y - [5] = \frac{-2}{5}(x - [-3])\\

                                               y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\   y =\frac{-2}{5}x-\frac{6}{5}-5\\\\   y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}

5 0
3 years ago
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