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Ket [755]
3 years ago
10

A rope 10 feet long is cut into two pieces. One piece is used to form a circle and the other used to form a square. Find a funct

ion representing the area of both square and circle as a function of the length of one side of the square.
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0
10-x=C=2πr

(10-x)/(2π)=r

A=π(100-20x+x^2)/(4π^2)

A=(x^2-20x+100)/(4π)

...

x/4=s, x=4s  using this in the area of a circle we get:

A=(16s^2-80s+100)/(4π)

A=(4s^2-20s+25)/π

And of course the area of a square is s^2

A=(4s^2+πs^2-20s+25)/π
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Which one doesn’t belong
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Answer:

x+5=5

Step-by-step explanation:

This is an equation where you are actually solving it. The others are expressions.

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3 years ago
PLS HELP ME solve the system of equations <br> all I need is to find x,y and z
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3 years ago
Let's play a game of Russian roulette. You are tied to your chair. Here's a gun, a revolver. Here's the barrel of the gun, six c
4vir4ik [10]

Answer:

Don't spin the barrel.

Step-by-step explanation:

Each time you spin the barrel, the probability A of finding a bullet, having two bullets in six chambers is:

P(A)=\frac{2}{6}=\frac{1}{3}=0.33

For you to get shot in the second try but not the first, the barrel spin would have to stop precisely at one specific chamber: the one right before the bullets, so that probability would be:

P(B)=\frac{1}{6}=0.17

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4 0
3 years ago
Find all the values of x in the set of complex numbers that satisfy the following equation:
Fynjy0 [20]
Compute all the component integrals first:

I_1=\displaystyle\int_0^{\pi/4}2\sec x\,\mathrm dx=2\ln(\sqrt2+1)
I_2=\displaystyle\int_0^2\ln x\,\mathrm dx=2(\ln2-1)
I_3=\displaystyle\lim_{a\to\infty}\int_{-a}^a\frac{\mathrm dx}{x^2+1}=\pi

Now,

\sqrt2\approx1.4\implies \sqrt2+1\approx2.4
\implies \left\lceil I_1\right\rceil=2

e
\implies\left\lfloor I_2\right\rfloor=-1

\pi\approx3.14\implies\left\lceil I_3\right\rceil=4

So the given equation reduces to

\displaystyle\sum_{k=-1}^2\frac{\mathrm d}{\mathrm dx}x^{k+2}=1-4!
\dfrac{\mathrm dx}{\mathrm dx}+\dfrac{\mathrm dx^2}{\mathrm dx}+\dfrac{\mathrm dx^3}{\mathrm dx}+\dfrac{\mathrm dx^4}{\mathrm dx}=-23
4x^3+3x^2+2x+24=0

a fairly standard cubic. Incidentally, when x=-2, the LHS reduces to 0, so x+2 is a factor of the cubic. You can find the remaining two solutions easily with the quadratic formula.
5 0
3 years ago
What is the measure of angle ACB?
S_A_V [24]
<ACB = 1/2(100 - 42)
<ACB = 1/2(58)
<ACB = 29

answer is A. 29
6 0
3 years ago
Read 2 more answers
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