A rope 10 feet long is cut into two pieces. One piece is used to form a circle and the other used to form a square. Find a funct
ion representing the area of both square and circle as a function of the length of one side of the square.
1 answer:
10-x=C=2πr
(10-x)/(2π)=r
A=π(100-20x+x^2)/(4π^2)
A=(x^2-20x+100)/(4π)
...
x/4=s, x=4s using this in the area of a circle we get:
A=(16s^2-80s+100)/(4π)
A=(4s^2-20s+25)/π
And of course the area of a square is s^2
A=(4s^2+πs^2-20s+25)/π
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