All categories

3 years ago

Volume kubus dengan panjang rusuk 2 cm?

Mathematics

2 answers:

jolli1 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

➡️ Volume = r³

➡️ 2³

➡️ 8

Agata [3.3K]3 years ago

7 0

= Sisi × Sisi × Sisi

= 2 Cm × 2 Cm × 2 Cm

= 4 Cm × 2 Cm

= 8 Cm .

Maka, volumenya 8 Cm.

You might be interested in

We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys

marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation

$\bar X=19.2$ represent the battery life sample mean

$\sigma=2.5$ represent the population standard deviation

$n=25$ sample size

$\mu_o =18$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:

Null hypothesis: $\mu = 18$

Alternative hypothesis: $\mu \neq 18$

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis: $\mu \leq 18$

Alternative hypothesis: $\mu > 18$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4$

4) P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=25-1=24$

Since is a two tailed test for parts I and II, the p value would be:

$p_v =2*P(t_{(24)}>2.4)=0.0245$

And for part III since we have a one right tailed test the p value is:

$p_v =P(t_{(24)}>2.4)=0.0122$

5) Conclusion

I. This finding is significant for a two-tailed test at .05.

Since the $p_v$ . We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0

3 years ago

The tubs are similar in shape.

faltersainse [42]

Answer:

The tube are similar in shape.

The height of the small tub is 5 cm.

The volume of the small tube is 150 cm3.

The volume of the large tub is 500 cm3.

Work out the height of the large tub.

Give your answer correct to 3 significant figures.

Step-by-step explanation: Hope this help(:

3 0

1 year ago

Read 2 more answers

Write an exponential model given the points ( 7, 12 ) and ( 8, 25 ). Round to the nearest hundredth.

inna [77]

Answer:

The exponential model is $y = 0.07\cdot e^{0.73\cdot x}$ .

Step-by-step explanation:

The exponential model can be modelled by the following mathematical expression:

$y = A\cdot e^{B\cdot x}$ (1)

Where:

$x$ - Independent variable.

$y$ - Dependent variable.

$A, B$ - Coefficients.

If we know that $(x_{1}, y_{1}) = (7,12)$ and $(x_{2}, y_{2}) = (8,25)$ , then we get the following system of equations:

$A\cdot e^{7\cdot B} = 12$ (2)

$A\cdot e^{8\cdot B} = 25$ (3)

If we divide (3) by (2), we calculate the value of $B$ :

$e^{B}=\frac{25}{12}$

$B = \ln \frac{25}{12}$

$B \approx 0.734$

And by (2), we determine the value of $A$ :

$A = 12\cdot e^{-7\cdot B}$

$A = 0.0704$

The exponential model is $y = 0.07\cdot e^{0.73\cdot x}$ .

4 0

3 years ago

(08.06)The following data show the weight, in ounces, of 10 different bags of candy: 10 3 7 3 4 21 6 10 1 2 4 After removing the

hoa [83]

Answer:

B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.

To find the mean absolute deviation, we first find the mean. Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):

(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5

Now we find the difference between each data point and the mean, take its absolute value, and find their sum:

|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =

5+2+2+2+1+1+5+4+3+1 = 26

We now divide this by the number of data points:

26/10 = 2.6

This is a measure of how much each bag of candy varies from the mean.

4 0

3 years ago

Read 2 more answers

Pls help me on this........

Shalnov [3]

The first one is the answer to the question

6 0

3 years ago

Read 2 more answers

Volume kubus dengan panjang rusuk 2 cm?​

Volume kubus dengan panjang rusuk 2 cm?