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4 years ago

What is the range of the function f(x)= 1/2sin(2x-pi)

Mathematics

1 answer:

Katen [24]4 years ago

8 0

Answer:

y=-1/2,y=3/2 -1/2<y<3/2

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Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.

Crank

Answer:

t = 10.2

Step-by-step explanation:

We have the following exponential equation.

$500(1.07)^{t} =1000$

We divide both sides by 500.

$(1.07)^{t} =2$

We apply logarithm to both sides.

$log(1.07)^{t} =log2$

We use the logarithm power rule.

$t.log(1.07) =log2\\t= log2/log1.07$

Finally, we solve for t.

t = 10.2

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4 years ago

PLEASE I REALLY NEED HELP ASAP DUO TOMORROW PLEASEEE

MariettaO [177]

maby it is :) (A) hope you do well

6 0

3 years ago

The binary operation* is defined on the set R of real numbers by X*Y = 3x + 3y - xy for all X , y E R. determine on the terms of

torisob [31]

Answer:

This is the Answer

Step-by-step explanation:

Pls mark as brainliest

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2 years ago

Pls help with this i'll give brainliest

ArbitrLikvidat [17]

Answer:

its 2 its right infront of you

Step-by-step explanation:

4 0

3 years ago

Plot the zeros of the polynomial y = x4 + 3x3 − 27x2 + 13x + 42

a_sh-v [17]

Answer:

See explanation

Step-by-step explanation:

Consider the polynomial $y=x^4+3x^3-27x^2+13x+42$ 4th power polynomial function has at most 4 zeros.

Integer zeros can be only among the divisors of 42:

$\pm1, \ \pm 2,\ \pm 3,\ \pm 6,\ \pm 7,\ \pm 14,\ \pm 21,\ \pm 42$

Check them:

$y(1)=1^4+3\cdot 1^3-27\cdot 1^2+13\cdot 1+42=1+3-27+13+42=32\neq 0\\ \\y(-1)=(-1)^4+3\cdot (-1)^3-27\cdot (-1)^2+13\cdot (-1)+42=1-3-27-13+42=0\\ \\y(2)=2^4+3\cdot 2^3-27\cdot 2^2+13\cdot 2+42=16+24-108+26+42=0\\ \\y(3)=3^4+3\cdot 3^3-27\cdot 3^2+13\cdot 3+42=81+81-243+39+42= 0\\ \\y(-7)=(-7)^4+3\cdot (-7)^3-27\cdot (-7)^2+13\cdot (-7)+42=2,401-1,029-1,323-91+42= 0$

Thus,

$y=(x+7)(x+1)(x-2)(x-3)$

Zeros are plotted in attached diagram.

4 0

4 years ago

Read 2 more answers