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Oxana [17]
3 years ago
11

Need help idk how to slove this

Mathematics
2 answers:
Gemiola [76]3 years ago
8 0

Hi!

I'm not sure how to slove this, but I do know how to solve it ;D

<h3>We can't know the exact value of y, but we can isolate y on one side. First, multiply by z on both sides. </h3>

\frac{x+y}{z*z}=3*z

x + y = 3 * z

<h3>Now subtract x from both sides.</h3>

x - x + y = 3 * z - x

<u>y = 3 * z - x</u>

<h2>The answer is y = 3 * z - x</h2>

Hope this helps! :)

-Peredhel

choli [55]3 years ago
6 0

Multiply both sides of this equation by Z.

This will eliminate the denominator on the left because Z over Z on the left cancels out. And now we have 3z on the right side.

x + y = 3z

Since we are to solve for y, we want to move x to the left by subtracting it from both sides.

y= 3z - x

This is as simplified as we can make it.


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Step-by-step explanation:

<h2><u>☼︎</u><u>Given :</u></h2>

  • The floor of a drawing room consist of 2000 tiles .Each tiles is rectangular in shape , of dimensions ,30 cm × 20 cm.

\rule{200pt}{3pt}

<h2><u>☼︎</u><u>To Find :</u></h2>

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\rule{200pt}{3pt}

<h2><u>☼︎</u><u>Solution :</u></h2>

<u>~ Formula </u><u>U</u><u>s</u><u>e</u><u>d</u><u>:</u>

\large{\blue{\bigstar}} \: \: {\underline{\boxed{\pink{\sf{ Area{\small_{(Rectangle)}} = Length \times Breadth }}}}} \: \: {\blue{\bigstar}}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

<u>~ Calculating the</u><u> Area of Tiles </u>

{➙ \: {\sf{ Area = Length \times Breadth}}}

{➙ \: {\sf{ Area = 30 \times 20 }}}

{\sf{➙ \: Area \:  of  \: 1 Tiles = {\purple{\bf{ 600 \: cm² }}}}}

\qquad{━━━━━━━━━━━━━━━━━━━━━}

<u>~ Calculating Area of the </u><u>Drawing Room :</u>

{➙ \: {\sf{ Area \: of \: Room \: = No. \: of \: Tiles \times Area \: of \: 1 \: Tile }}}

{➙ \: {\sf{ Area \: of \: Room \: = 2000 \times 600 }}}

{\qquad{\sf{ Area \: of \: Room \: = {\color{darkblue}{\bf{ 1200000 \: cm² }}}}}}

\qquad{━━━━━━━━━━━━━━━━━━━━━}

<u>~ Therefore :</u>

❝ Area of the Drawing room is 1200000 cm² or 12000 m² . ❞

\begin{gathered} \\ {\blue{\underline{\red{\rule{300pt}{9pt}}}}}\end{gathered}

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