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Katyanochek1 [597]
3 years ago
7

Write an equation of the line with a slope of — 7 and y-intercept of 1.

Mathematics
1 answer:
loris [4]3 years ago
7 0

Answer:

y= -7x + 1

Step-by-step explanation:

this is the answer

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Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketbal
sweet-ann [11.9K]

Answer: First Option is correct.

Step-by-step explanation:

Since we have given that

Mean (\mu)= 70 inches

Standard deviation (\sigma)= 3 inches

Average basket ball player (\bar{X}) = 79 inches

Since it is normally distributed assume with 5% significance .

So, it becomes,

Z>\frac{\bar{X}-\mu}{\sigma}\\\\Z>\frac{79-70}{3}\\\\Z>\frac{9}{3}\\\\Z>3\\\\\therefore\ P(Z>3)=1-0.9987=0.0013

At 0.05 level of significance , 0.0013 = 0.13% of the adult male population is taller than the average basketball player .

Hence, First Option is correct.

5 0
3 years ago
Read 2 more answers
hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
cricket20 [7]

Answer:

The answer is H

Step-by-step explanation:

Next time pls ask real question

8 0
2 years ago
A ball is thrown vertically in the air with a velocity of 95 ft/s. The ball is at a height of 120 ft.
sattari [20]

Answer:

The ball is at a height of 120 feet after 1.8 and 4.1 seconds.

Step-by-step explanation:

The statement is incomplete. The complete statement is perhaps the following "A ball is thrown vertically in the air with a velocity of 95 ft/s. What time in seconds is the ball at a height of 120ft. Round to the nearest tenth of a second."

Since the ball is launched upwards, gravity decelerates it up to rest and moves downwards. The position of the ball can be determined as a function of time by using this expression:

y = y_{o} + v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}

Where:

y_{o} - Initial height of the ball, measured in feet.

v_{o} - Initial speed of the ball, measured in feet per second.

g - Gravitational constant, equal to -32.174\,\frac{ft}{s^{2}}.

t - Time, measured in seconds.

Given that y_{o} = 0\,ft, v_{o} = 95\,\frac{ft}{s}, g = -32.174\,\frac{ft}{s^{2}} and y = 120\,ft, the following second-order polynomial is found:

120\,ft = 0\,ft + \left(95\,\frac{ft}{s} \right)\cdot t +\frac{1}{2}\cdot \left(-32.174\,\frac{ft}{s^{2}} \right) \cdot t^{2}

-16.087\cdot t^{2} + 95\cdot t -120 =0

The roots of this polynomial are, respectively:

t_{1} \approx 4.075\,s and t_{2} \approx 1.831\,s.

Both roots solutions are physically reasonable, since t_{1} represents the instant when the ball reaches a height of 120 ft before reaching maximum height, whereas t_{2} represents the instant when the ball the same height after reaching maximum height.

In nutshell, the ball is at a height of 120 feet after 1.8 and 4.1 seconds.

8 0
3 years ago
When one element replaces another element in a compound the reaction is a___ reaction
vampirchik [111]

Answer:

single replacement lol

Step-by-step explanation:

7 0
3 years ago
I do not understand!!help please?!
blsea [12.9K]

Answer:

a. (3x^4 + 6 ) + (2x^2)

b. (X^3 ) + (-x -7)

c. (4.6x^4) + (-1.5x^2)

Step-by-step explanation:

For the first one, we have to write to polynomials, which equal 3x^4 + 2x^2 +6

One possible solution is (3x^4 + 6 ) + (2x^2)

For b, we can do,

(X^3 ) + (-x -7)

And finally for c, we can write,

(4.6x^4) + (-1.5x^2)

5 0
3 years ago
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