Answer: 25% of the heterozygous cross are short, and the offspring of a homozygous dominant and homozygous recessive pea plant will always display the dominant trait (phenotype), because they are heterozygous.
Explanation:
In this explanation, I'm assuming that the allele "T" for tall plants is dominant to the allele "t" for short plants, like in Gregor Mendel's pea plant experiment.
A homozygous tall pea plant will have the genotype "TT" and a homozygous short plant will have the genotype "tt" because homozygous means that both alleles are identical. Since "T" is dominant over "t", any plant with at least one "T" allele will be tall (the dominant trait), regardless of what the other allele is. Let's look at a Punnett square for this cross:
Each of the offspring has one "T" allele, so they are all tall plants. This is because the "T" allele is dominant over the "t" allele, so a plant with one "t" allele and one "T" allele will only display the traits of the "T" allele, which in this case is a tall pea plant.
If we cross the offspring, we get a Punnett square that looks like this:
The "TT" and "Tt" crosses both have at least one "T" allele, so they are tall plants. However, the last cross "tt" doesn't have any "T" alleles and is short, because it is homozygous recessive . Since 1 out of 4 pea plants are short, or 1/4, the probability of a short pea plant from a heterozygous cross is 25%.
The ICD-10-PCS coding guidelines have need of that the coder to do both percutaneous endoscopic inspection and open resection of the gallbladder. In addition, laparoscopic cholecystectomy is a process in instance that the gallbladder is detached by the use of laparoscopic methods. The laparoscopic surgery also denoted to as slightly hostile surgery that defines the enactment of surgical techniques with the help of a video camera and several thin tools while a cholecystectomy may be essential if a person is experiencing aching from gallstones that block the movement of bile. A cholecystectomy is a common surgery and it brings only a small possibility of impediments.
The atrioventricular valves.
Answer:
Hydrogen Bonds Make Water Sticky
Explanation:
Hydrogen bonds form when hydrogen atoms covalently bonded to nitrogen (N), oxygen (O), or fluorine (F) in the form of covalent compounds such as ammonia (NH3), water (H2O) and hydrogen fluoride gas (HF). In these molecules, the hydrogen atoms do not pull as strongly on the shared electrons as the N, O, or F atoms. Therefore, the molecules are polar; the hydrogen atoms become positively charged and are able to form hydrogen bonds to negative ions or negatively charged parts of other molecules (such as the N, O, and F atoms that become negatively charged in these compounds).
Answer:
The only possible answer is D, which states that the population will reach 5000 and after that the growth will stabilise (exactly what would hapen in a logistic growth).
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