Parents that are heterozygous for having freckles (dominant) are crossed.

Biology

1 answer:

sergiy2304 [10]3 years ago

6 0

Answer:

Phenotypic ratio - 3 Freckes : 1 No freckles

Explanation:

This question represents a monohybrid cross i.e. involving a single gene coding for possession or not of freckles. The allele for possession of freckles (F) is dominant over the allele for no freckles (f).

In a cross between two HETEROZYGOUS parents i.e. Ff × Ff, each parent will produce gametes with alleles F and f respectively. Using a punnet square (see attached image), four possible offsprings will be produced with genotypes: FF, Ff, Ff and ff.

Based on this genotypes, the phenotypic ratio of the offsprings will be 3:1 where 3 offsprings will possess freckles and 1 will have no freckles.

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