Parents that are heterozygous for having freckles (dominant) are crossed.
1 answer:
Answer:
Phenotypic ratio - 3 Freckes : 1 No freckles
Explanation:
This question represents a monohybrid cross i.e. involving a single gene coding for possession or not of freckles. The allele for possession of freckles (F) is dominant over the allele for no freckles (f).
In a cross between two HETEROZYGOUS parents i.e. Ff × Ff, each parent will produce gametes with alleles F and f respectively. Using a punnet square (see attached image), four possible offsprings will be produced with genotypes: FF, Ff, Ff and ff.
Based on this genotypes, the phenotypic ratio of the offsprings will be 3:1 where 3 offsprings will possess freckles and 1 will have no freckles.
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