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lozanna [386]
3 years ago
10

Evaluate the limit. lim x ? 5 (x-5)^2/x-5

Mathematics
1 answer:
slega [8]3 years ago
7 0
As x approaches 5
hmm, we can divide the (x-5) from top and bottom to get x-5
if we input 5 for x we get
5-5=0
it approaches 0 as x approaches 5
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Excited about the success of celebrity​ stamps, post office officials were rumored to have put forth a plan to institute two new
SVETLANKA909090 [29]

Answer:

E=2.8 m-40

Step-by-step explanation:

We konw that  30°E=25°M and 310°E=125°M

so if we want to write an ecuation that linearly relates E with M, we can use the formula of the line that crosses two points:

Y-y1= (y2-y1)/(x2-x1)*(X-x1)

In thts case:

  • Y=E
  • y1= E1= 30
  • y2= E2=310
  • x1= M1= 25
  • x2=M2=125

so

E-E1= (E2-E1)/(M2-M1)* (M-M1)

E-30 = (310-30)/(125-25)*(M-25)

E-30 =280/100 *(M-25)

E-30 =2.8 M- 280*25/100

E-30 =2.8 M-70

E= 2.8 M-70+30

E=2.8 M-40

Good luck!

8 0
3 years ago
(Sec. 2.3) A restaurant having a grand opening is allowing visitors to try 6 different free samples from a selection. Options fo
Akimi4 [234]

Answer:A)35choices

B)475,020choices

C)132choices

D)0.000278

E)0.000166

Step-by-step explanation:

Given 7poultry items represented by 7p

10 red meat items=10R

12 vegetarian items=12V

@

A)there are 7combination 3ways of selecting 3out of 7 poultry items

From the formula nCr=n!/(n-r)!r!

7C3=7!/(7-3)!3!=7!/4!×3!=35choices

b)total items available=7p+10R+12V(denotation explained above)=29items

Choosing 6items implies

29C6=29!/(29-6)!×6!

29!/23!×6!=475,020 ways

C)7C2+10C2+12C2

7!/5!2!+10!/8!2!+12!/10!2!

21+45+66=132 choices

D) probability (choosing 2items from each class)=

7C2+10C2+12C2/29C6

Where 29C6 represent total probable.

21+45+66/29!/23!6!

=132/475020=0.000278choices

E)for meats to be in the majority on a 6choices selection impliee that vegetarian items will be

0,1 or2i.e combination of vegetarian and meat will be(0,6)or(1,5)or(2,4) .

Prob(0veg)+prob(1veg item) or prob(2veg items)

12C0+12C1+12C2/29C6

=1+12+66/475,020

=0.000166

5 0
3 years ago
A dress is on sale for 75% off. The sale price is $30. How much did the dress originally cost
lesya [120]

The dress originally costs $120.

In order to find this, you need to divide the current cost by the percentage you are paying for. Since it's 75% off, you are paying for 25% of the dress's original cost. Therefore, divide 30 by 25%.

30/.25 = $120

7 0
3 years ago
Read 2 more answers
The table below shows data from a survey about the amount of time students spend doing homework each week. The students were in
nadezda [96]

Answer:

The correct option is;

Both spreads are best described by the standard deviation

Step-by-step explanation:

The given information are;

,                                    College                       High School

High,                              20                               20

Low,                                6                                 3

Q₁,                                   8                                 5.5

Q₃,                                  18                                16

IQR,                                 10                                10.5

Median,                           14                                11

Mean,                              13.3                             11

σ,                                      5.2                             5.4

Checking for outliers, we have

College

Q₁ - 1.5×IQR gives 8 - 1.5×10 = -7

Q₃ + 1.5×IQR gives 18 + 1.5×10 = 33

For high school

Q₁ - 1.5×IQR gives 5.5 - 1.5×10.5 = -10.25

Q₃ + 1.5×IQR gives 16 + 1.5×10.5 = 31.75

Therefore, there are no outliers and the data is representative of the population

From the data, for the college students, it is observed that the difference between the mean, 13.3 and Q₁, 8, and between Q₃, 18 and the mean,13.3 is approximately the standard deviation, σ, 5.2

The difference between the low and the high is also approximately 3 standard deviations

Therefore the college spread is best described by the standard deviation

Similarly for the high school students, the IQR is approximately two standard deviations, the  difference between the mean, 11 and Q₁, 5.5, and between Q₃, 16 and the mean,11 is approximately the standard deviation, σ, 5.4

Therefore the high school spread is also best described by the standard deviation.

4 0
3 years ago
Mrs. Logan's class is hiking. They increase their elevation by 100 ft every 2 min. What is the rate of their climbing?
Ainat [17]

Answer: B

Step-by-step explanation:

100 feet every 2 minutes

100 divided by 2 is 50

50 ft per minute

B is the answer

8 0
2 years ago
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