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lozanna [386]
3 years ago
10

Evaluate the limit. lim x ? 5 (x-5)^2/x-5

Mathematics
1 answer:
slega [8]3 years ago
7 0
As x approaches 5
hmm, we can divide the (x-5) from top and bottom to get x-5
if we input 5 for x we get
5-5=0
it approaches 0 as x approaches 5
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two cruise ships are sailing towards each other from caribbean islands that are 264 km apart, one ship travels 4 km/h faster tha
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The answer should be 1,056 

If not sorry. 

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3 years ago
What should the next number be? 100 96 104 88 120 56
riadik2000 [5.3K]

100 ---> 96 is -4

96 ---> 104 is +8

104 ---> 88 is -16

88 ---> 120 is +32

120 ---> 56 is -64  

So first we go down by 4, then up by 8, then down 16, then up 32, then finally down 64.  

The pattern of numbers is: -4, +8, -16, +32, -64  

Notice it's the powers of 2:  

2^2 = 4

2^3 = 8

2^4 = 16

2^5 = 32

2^6 = 64

each term doubles. Also each term alternates in sign. One is positive, then the next is negative and so on.  

The last difference is -64, which doubles to -128. Change the sign to positive to get +128  

Add 128 to the last term of 56 to get

128+56 = 184  

Therefore, the final answer is 184

8 0
3 years ago
How many 5-minute calls can you make if your phone plan gives you 200 minutes per month?
Inessa [10]

Answer:

40 minutes

Step-by-step explanation:

You can simply make 200/5 = 40 5 minute calls per month.

This works because every call is a 5-minute call.  So then we just have to find how many times we can make a 5-minute call up to 200 minutes.  We already have an operation for this: Division.  This acts as the opposite of multiplication and speeds our process up.

5 0
3 years ago
Read 2 more answers
Write as a demical: Michael brings 6 pounds of rice to his mom's house there are a total of 10 people attending the dinner if th
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3 years ago
Y = x^2+5x-3<br> y-x=2<br><br> What is the solution of the linear-quadratic system of equations
Sunny_sXe [5.5K]

Answer:

(-5,-3)

(1,3)

Step-by-step explanation:

Solving with substitution

Set both equations to y =  ...

y = x^2 + 5x - 3

----------------

y - x =2

y = x + 2

----------------

Substitute one of the Y's with the other Y = equation.

x + 2 = x ^2 + 5x -3

Set one side to 0

0 = x^2 + 4x -5

x^2 + 4x - 5 = 0

Simplify by factoring

(x-1) (x+5)

Get your X values

x-1 = 0

x = 1

x+5 = 0

x = -5

Plug in each X into one of the equations to get your Y value.

1st X

y = x + 2

y = 1 + 2

y = 3

When X = 1, Y = 3

2nd X

y = x + 2

y = -5 + 2

y = -3

When X = - 5, Y = -3

Your answers are (1,3) and (-5,-3)

8 0
2 years ago
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