Answer:
<h2>
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Step-by-step explanation:
Answer:
The height of the tree is H = 77.06 m
Step-by-step explanation:
From Δ ABC
AB = height of the tree
h = 0.9623 x ------- (1)
From Δ ABD
h = 0.77 (x + 20) ----- (2)
Equating Equation 1 & 2 we get
0.9623 x = 0.77 (x + 20)
0.9623 x = 0.77 x + 15.4
x (0.1923) = 15.4
x = 80.08 m
Thus the height of the tree is given by
H = 0.9623 x
H = 0.9623 × 80.08
H = 77.06 m
Therefore the height of the tree is H = 77.06 m
Answer: It is not possible that two triangles that are similar and not congruent in spherical geometry.
Step-by-step explanation:
For instance, taking a circle on the sphere whose diameter is equal to the diameter of the sphere and inside is an equilateral triangle, because the sphere is perfect, if we draw a circle (longitudinal or latitudinal lines) to form a circle encompassing an equally shaped triangle at different points of the sphere will definately yield equal size.
in other words, triangles formed in a sphere must be congruent and also similar meaning having the same shape and must definately have the same size.
Therefore, it is not possible for two triangles in a sphere that are similar but not congruent.
Two triangles in sphere that are similar must be congruent.
In order to reduce ANY fraction to lowest terms, find any common factors
of the numerator and denominator, and divide them both by it. If they still
have a common factor, then divide them by it again. Eventually, they won't
have any common factor except ' 1 ', and then you'll know that the fraction is
in lowest terms.
Do 15 and 40 have any common factors ?
Let's see . . .
The factors of 15 are 1, 3, <em>5</em>, and 15 .
The factors of 40 are 1, 2, 4,<em> 5</em>, 8, 10, 20, and 40 .
Ah hah ! Do you see that ' <em>5</em> ' on both lists ? That's a common factor.
So 15/40 is NOT in lowest terms.
Divide the numerator and denominator both by 5 :
15 / 40 =<em> 3 / 8</em>
3 and 8 don't have any common factor except ' 1 '.
So 3/8 is the same number as 15/40, but in lowest terms.
Step-by-step explanation:
6ac+10ac
2ac(6ac+10ac)
2ac(3+5)
