Answer:
- D(5, 4), E(14, 7), M(9.5, 5.5)
Step-by-step explanation:
As AD = 1/4AB and DE ║ AC, the ratio CE/CB = 1/4, or CE = 1/4CB
<u>Find the coordinates of D:</u>
- x = 1 + 1/4(17 - 1) = 1 + 4 = 5
- y = 5 + 1/4(1 - 5) = 5 - 1 = 4
<u>Find the coordinates of E:</u>
- x = 13 + 1/4(17 - 13) = 13 + 1 = 14
- y = 9 + 1/4(1 - 9) = 9 - 2 = 7
<u>Find the coordinates of the midpoint M of DE:</u>
- x = (5 + 14)/2 = 19/2 = 9.5
- y = (4 + 7)/2 = 11/2 = 5.5
Answer:
20cm rounded to the nearest tenth is 20cm
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Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
Answer:
will be the fraction.
Step-by-step explanation:
Here the recurring decimal number is 0.0343434....
To convert this recurring decimal to fraction we assume,
x = 0.03434.... -------(1)
Now multiply both the sides with 100.
100x = 3.43434.... ------(2)
Now subtract equation (1) from equation (2).
100x = 3.43434
<u> x = 0.03434</u>
99x = 3.4
x = 
= 
x =
Therefore, fraction that represents the decimal number is
So you multiply 2 1/3times 1 1/2 and you get 3 and 1/6
