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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics

2 answers:

Ahat [919]3 years ago

8 0

Answer:

The answer is -x^2+7x+1 I think

Step-by-step explanation:

Viktor [21]3 years ago

8 0

Answer: (D) y = x² + 7x + 1

Step-by-step explanation:

Since a table of x,y-values are given, choose a coordinate and plug it into each equation to see which results in a true statement. If more than one equation is true, then choose another coordinate and plug it into the true equations from the previous coordinate.

Let's try (0, 1):

(A) y = x² - 7x - 1

1 = (0)² - 7(0) - 1

1 = -1

FALSE, So A is not the quadratic equation we are looking for

(B) y = x² - 7x + 1

1 = (0)² - 7(0) + 1

1 = 1

TRUE, So B could be the quadratic equation we are looking for

1 = -(0)² + 7(0) + 1

1 = 1

TRUE, So C could be the quadratic equation we are looking for

(D) y = x² + 7x + 1

1 = (0)² + 7(0) + 1

1 = 1

TRUE, So D could be the quadratic equation we are looking for

Let's try (1, 9) for B, C, and D:

(B) y = x² - 7x + 1

9 = (1)² - 7(1) + 1

9 = -5

FALSE, So B is not the quadratic equation we are looking for

9 = -(1)² + 7(1) + 1

9 = 7

FALSE, So C is not the quadratic equation we are looking for

(D) y = x² + 7x + 1

9 = (1)² + 7(1) + 1

9 = 9

TRUE, So D is the quadratic equation we are looking for!

You might be interested in

Does the table show a direct proportional relationship? If so, what is the constant of proportionality?

lesantik [10]

Answer:

C. Yes, 3.5.

Step-by-step explanation:

If there is a relationship of direct proportionality for every ordered pair of the table, then the constant of proportionality must the same for every ordered pair. The constant of proportionality ( $k$ ) is described by the following expression:

$k = \frac{y}{x}$ (1)

Where:

$x$ - Input.

$y$ - Output.

If we know that $(x_{1}, y_{1}) = (13, 45.5)$ , $(x_{2}, y_{2}) = (14, 49)$ and $(x_{3}, y_{3}) = (15, 52.5)$ , then the constants of proportionalities of each ordered pair are, respectively:

$k_{1} = \frac{y_{1}}{x_{1}}$

$k_{1} = \frac{45.5}{13}$

$k_{1} = \frac{7}{2}$

$k_{2} = \frac{y_2}{x_2}$

$k_{2} = \frac{49}{14}$

$k_{2} = \frac{7}{2}$

$k_{3} = \frac{y_{3}}{x_{3}}$

$k_{3} = \frac{52.5}{15}$

$k_{3} = \frac{7}{2}$

Since $k_{1} = k_{2} = k_{3}$ , the constant of proportionality is 3.5.

8 0

3 years ago

Simplify each expression. (4 - 2i) - (-3 + i)

PtichkaEL [24]

Answer:

2i - (-3 + i)

Step-by-step explanation:

I think this is it. Sorry if it's wrong

7 0

2 years ago

Read 2 more answers

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago

What is the radius of the cylinder ?

djyliett [7]

Answer:

The radius is 1

Step-by-step explanation:

7 0

3 years ago

julie has 10 yards of ribbon she divides the ribbon into 3 equal pieces and uses 2 of the pieces on gifts how much ribbon does s

Lunna [17]

Answer:

2/3

Step-by-step explanation:

if we divide 10 by 3 then we get 3.3 repeating so just use the fraction 1/3. if you use 2 of the divided lengths then you get 2/3

4 0

3 years ago