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3 years ago

How to slove for extraneous solutions

Mathematics

1 answer:

Snezhnost [94]3 years ago

5 0

The answer is 23
HOPED THIS HELPED :)

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-3*6<br> Multiplying and dividing integers

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All we need to do is multiply.

-3 * 6 = -18

Anytime you multiply a negative number to a positive number, its always going to be negative.

Best of Luck!

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2 years ago

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Ulleksa [173]

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Step-by-step explanation:

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3 years ago

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Aneli [31]

Answer: 25x^2 - 1^2

Explanation:

(5x+1) (5x-1)

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1 year ago

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2 years ago

The heat index I is a measure of how hot it feels when the relative humidity is H (as a percentage) and the actual air temperatu

PSYCHO15rus [73]

Answer:

a) $I(95,50) = 73.19$ degrees

b) $I_{T}(95,50) = -7.73$

Step-by-step explanation:

An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

$I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}$

a) Calculate I at (T ,H) = (95, 50).

$I(95,50) = 45.33 + 0.6845*(95) + 5.758*(50) - 0.00365*(95)^{2} - 0.1565*95*50 + 0.001*50*95^{2} = 73.19$ degrees

(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.

This is the partial derivative of I in function of T, that is $I_{T}(T,H)$ . So

$I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}$

$I_{T}(T,H) = 0.6845 - 2*0.00365T - 0.1565H + 2*0.001H$

$I_{T}(95,50) = 0.6845 - 2*0.00365*(95) - 0.1565*(50) + 2*0.001(50) = -7.73$

8 0

3 years ago