1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bogdan [553]
3 years ago
12

(a) If an object travels along a line with constant velocity −24 ms, then the general formula for the position of the object is_

_____________.
Physics
1 answer:
postnew [5]3 years ago
7 0

Mathematically we know that the position is the integral of the velocity as a function of time, that is, the general formula for determining the position as a function of velocity would be given by

x(t) = x_0 +\int_0^t vdt

Here

x_0 represents the initial position, and the integral, the position with respect to the speed of the object within a certain time

Replacing and considering that there is no starting position,

v(t) = -24

x (t) = -24 \int dt

x(t) = -24t+C

You might be interested in
An apple is held completely submerged just below the surface of water in a container. The apple is then moved to a deeper point
kodGreya [7K]

Answer:

c- the same

Explanation:

There will be apparent  reduction in the weight of the apple due to buoyant force acting on it in upward direction . The magnitude of upward directing buoyant force will be equal to weight of water displaced . The weight of displaced water will remain same if it is completely submerged in water and it is moved from one point to another inside water. So in the given two cases , weight of displaced water will same . Hence the buoyant force too will remain same . Hence the apparent weight too will be same .

So force required to hold apple at deeper point inside water will remain same.

6 0
3 years ago
What did jesseca kusher make
fiasKO [112]

I have no idea... Sorry :D

4 0
3 years ago
The δe of a system that releases 12.4 j of heat and does 4.2 j of work on the surroundings is __________ j.
Vedmedyk [2.9K]

The answer for this problem is clarified through this, the system is absorbing (+). And now see that it uses that the SURROUNDINGS are doing 84 KJ of work. Any time a system is overshadowing work done on it by the surroundings the sign will be +. So it's just 12.4 KJ + 4.2 = 16.6 KJ.

5 0
4 years ago
If it takes 100 N to get a 10 kg object to accelerate at 10m/s/s, how much force will it take to get a 20 kg object to accelerat
yan [13]

Answer: C) 200 N

Explanation:

The force F is defined as:

F=m.a

Where:

m=20 kg is the mass of the object

a=10 m/s^{2} is the acceleration

Then:

F=(20 kg)(10 m/s^{2})

Finally:

F=200 N

Hence, the correct option is C.

7 0
3 years ago
What is Quantum Physics?
vredina [299]
Study of interaction between matter and energy using mechianical description
8 0
4 years ago
Other questions:
  • the distance between the sun and earth is about 1.5X10^11 m. express this distance with an SI prefix and kilometers
    5·1 answer
  • An electric iron operating at 120 volts draws 10. amperes of current. how much heat energy
    9·1 answer
  • Which behavior is a warning sign of a bully?
    15·2 answers
  • A geologist finds an area of undisturbed sedimentary rock the lowest layer is most likely the _____?
    8·1 answer
  • This table shows the pH values of different solutions
    14·1 answer
  • Weight is related to mass but they are not the same. What is weight defined?
    10·1 answer
  • A 1,700kg car is being used to give a 1,400kg car a push start by exerting a force of 140N the impulse on the smaller car during
    8·1 answer
  • Help plz will give brainliest and dont answer if u dont know
    5·2 answers
  • An ant is dragging a house-fly and the elephant is pushing a big tree which is not moving. who is doing work, the ant or the ele
    11·1 answer
  • A post driver has a mass of 10kg. Calculate the change in GPE stored when the post driver is lifted by 50cm above the post. The
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!