1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denpristay [2]
2 years ago
14

A post driver has a mass of 10kg. Calculate the change in GPE stored when the post driver is lifted by 50cm above the post. The

gravitational field strength on earth is 10N/kg.
Physics
1 answer:
elixir [45]2 years ago
7 0

Answer:

500kJ

Explanation:

Common equation;

GPE = mgh

m = mass - in kg

g = gravitational field strength - in N/kg

h = height lifted/lowered - in meters

GPE = 10kg × 10N/kg × 5000m

GPE = 500000Nm

GPE = 500000J

GPE = 500kJ

Please mark me branliest thank you!!!!!!!

You might be interested in
Pete is driving down a highway and sees a brown sign. All of the brown signs
pychu [463]

Answer:

C

Explanation:

He was using visual clues to read the signs.

6 0
3 years ago
If the sun's mass is about average, how many stars are there in the milky way galaxy? the mass of the sun is of the order of 103
ra1l [238]
Just assume that the sun has the average mass of all the stars
Then divide the mass of the galaxy by the mass of the sun. 
<span>10^30 has 30 zeroes after it. 10^42 has 42 zeroes.

The answer would have 12 zeroes which concludes a trillion stars. </span>
4 0
4 years ago
Read 2 more answers
A 45.0 g hard-boiled egg moves on the end of a spring with force constant 25.0 N/m. Its initial displacement 0.500 m. A damping
leva [86]

Answer:

0.02896 kg/s

Explanation:

A_1 = Initial displacement = 0.5 m

A21 = Final displacement = 0.1 m

t = Time taken = 0.5 s

m = Mass of object = 45 g

Displacement is given by

x=Ae^{-\dfrac{b}{2m}t}cos(\omega t+\phi)

At maximum displacement

cos(\omega t+\phi)=1

\\\Rightarrow A_2=A_1e^{-\dfrac{b}{2m}t}\\\Rightarrow \dfrac{A_1}{A_2}=e^{\dfrac{b}{2m}t}\\\Rightarrow ln\dfrac{A_1}{A_2}=\dfrac{b}{2m}t\\\Rightarrow b=\dfrac{2m}{t}\times ln\dfrac{A_1}{A_2}\\\Rightarrow b=\dfrac{2\times 0.045}{5}\times ln\dfrac{0.5}{0.1}\\\Rightarrow b=0.02896\ kg/s

The magnitude of the damping coefficient is 0.02896 kg/s

6 0
4 years ago
Dennis throws a volleyball up in the air. It reaches its maximum height 1.1\, \text s1.1s1, point, 1, start text, s, end text la
rewona [7]

Answer:

If max height = 1.1 meters, then initial velocity is 3.28 m/s

If max height is 1.1 feet, then the initial velocity is 5.93  ft/s

Explanation:

Recall the formulas for vertical motion under the acceleration of gravity;

for the vertical velocity of the object we have

v=v_0-g \,t

for the object's vertical displacement we have

y-y_0=v_0\,t - \frac{g}{2} \,t^2

If the maximum height reached by the object is given in meters, we use the value for g in m/s^2 which is: 9.8\,\,m/s^2

If the maximum height of the object is given in feet, we use the value for g in  ft/s^2  which is : 32\,\,ft/s^2

Now, when the ball reaches its maximum height, the ball's velocity is zero, so that allows us to solve for the time (t) the process of reaching the max height takes:

v=v_0-g \,t\\0=v_0-g \,t\\g\,\,t=v_0\\t=\frac{v_0}{g}

and now we use this to express the maximum height in the second equation we typed:

y-y_0=v_0\,t - \frac{g}{2} \,t^2\\max\,height=v_0\,(\frac{v_0}{g})  - \frac{g}{2} \,(\frac{v_0}{g})^2\\max\,height= \frac{v_0^2}{2\,g}

Then if the max height is 1.1 meters, we use the following formula to solve for v_0:

1.1= \frac{v_0^2}{2\,9.8}\\(9.8)\,(1.1)=v_0^2\\v_0=10.78\\v_0=\sqrt{10.78} \\v_0=3.28\,\,m/s

If the max height is 1.1 feet, we use the following formula to solve for v_0:

1.1= \frac{v_0^2}{2\,32}\\(32)\,(1.1)=v_0^2\\v_0=35.2\\v_0=\sqrt{35.2} \\v_0=5.93\,\,ft/s

5 0
3 years ago
Read 2 more answers
How to play track and field
Ahat [919]

Explanation:

Track and Field is a sport, which is includes disciplines of running, jumping, and throwing events. The sport traces back to Ancient Greece. The first recorded examples of this sport were at the Ancient Greek Olympics. In Ancient Greece, only one event was contested, the stadion footrace. Later on, the game expanded to more events.Events of track and field are divided into three: track events, field events, and combined events. Track events consist of Sprints, middle-distance, long distance, hurdles and relays; Field events consist of jumps and throws; while combined events consist of pentathlon, heptathlon, and decathlon. Track and field is usually played outdoors in stadiums. The usual features of a track and field stadium are the outer running track, and the field within the track

3 0
3 years ago
Read 2 more answers
Other questions:
  • 3 types of acceleration
    5·2 answers
  • Un móvil, que sale desde un punto situado 3 metros a la izquierda del origen y lleva un movimiento uniforme, se sitúa a 12 metro
    6·1 answer
  • What metric unit would you use to estimate the actual distance between Boston and New York?
    14·1 answer
  • Calculate the average speed (in km/h) of a car stuck in traffic that drives 12 kilometers in 2 hours.
    12·1 answer
  • A bicycle has wheels with a diameter of 0.630 m. It accelerates uniformly and the rate of rotation of its wheels increases from
    6·1 answer
  • "Two rooms are connected by a doorway. You are in one room and your friend is in the other room. Explain why you can hear your f
    7·2 answers
  • What are the particles called in a current??
    6·2 answers
  • Newton's first law of motion says (in part) that an object in motion will remain in motion at a constant speed and in a straight
    13·2 answers
  • How does social theory learning impact on children​
    10·1 answer
  • Which part of the eye is used to see things in high detail?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!