Answer:
The work done to pump all of the kerosene from the tank to an outlet is
Step-by-step explanation:
The work is defined by:
(1)
The force here will be the product between the volume and the kerosene weighing, so we have :
This force will be in-lbs.
Where R is the radius (3 feet)
Then using (1), we have:
Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.
Therefore, the work done to pump all of the kerosene from the tank to an outlet is
I hope it helps you!
Answer:
Angle of A = 90 degree-62 degree = 28 degree.
Step-by-step explanation:
tan (62) = opposite / adjacent = 10 / a ---> a = 10/tan (62) = 10/ 1.88 = 5.319
cos (62) = a/c --->c = a/cos (62) = 5.319 / 0.47 = 5.3 / 0.47 = 11.3
or another way.
sin (62) = 10 /c ---> c = 10/ sin (62) = 10 / 0.88 = 11.3
So Angle of A = 28 degree.
a = 5. 3
c = 11.3.
please give me brainliest. I hope it help.
Answer:
−33999/50
Step-by-step explanation:
2/100−680
=
1/50−680
=
−33999/50
With respect to the parent function,
y = 1/(x+5) +2
is translated 5 units left and 2 units up.