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Greeley [361]
3 years ago
5

Factor completely. a^2 - 25b^2

Mathematics
1 answer:
pshichka [43]3 years ago
5 0
Hello : 
<span>Factor completely. a^2 - 25b^2 :
a²-25b²=a²-(5b)² = (a-5b)(a+5b)</span>
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2. Create an estimated probability distribution for the time teens spend texting.
Furkat [3]

Answer:

<u><em>Hours</em></u>          0     0.5    1.0     1.5    2.0    2.5    3.0    3.5    4.0    4.5    5.0

<u><em>Frequency</em></u>* 0.2  0.09  0.25  0.18  0.11  0.07  0.05  0.02  0.01  0.02  0.01

Problem Statement:

The table shows the number of hours, to the nearest half hour per day, that teens spend texting according to a random sample of 870 teenagers aged 13–18 in a large urban city.

Hours          0     0.5    1.0   1.5  2.0   2.5  3.0  3.5  4.0  4.5  5.0

Frequency  170  82    220  153  92   58   40    15  12   18    10

Step-By-Step Explanation:

As we need the estimated probability distribution for teens spending time texting, we will be needing the total sample size.

As given in the problem statement,

<em><u>Total Sample Size = 870</u></em>

To calculate estimated probability distribution, we will convert the frequency sample into estimated probability distribution, for that:

Estimated Probability Distribution (Frequency*)=\frac{Frequency.Sample.Size.of.that.hour}{Total.Sample.Size}

<u><em>For Example:</em></u>

Estimated probability distribution that teens spend 0 hours texting=\frac{170}{870} =0.20

Similarly

Estimated probability distribution that teens spend 0.5 hours=\frac{82}{870} =0.09

Using the same formula we get:

<em><u>Hours</u></em>          0     0.5    1.0     1.5    2.0    2.5    3.0    3.5    4.0    4.5    5.0

<em><u>Frequency</u></em>* 0.2  0.09  0.25  0.18  0.11  0.07  0.05  0.02  0.01  0.02  0.01

(<em>Note: Frequency* is the estimated probability distribution)</em>

4 0
4 years ago
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