<span>Let x = the width
:
It says,"The length of a rectangle is 4 less than 3 times the width." write that as:
L = 3x - 4
:
If the perimeter is 40, find the dimensions of the rectangle.
:
We know: 2L + 2W = 40
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Substitute (3x-4) for L and x for W
2(3x-4) + 2x = 40
:
6x - 8 + 2x = 40; Multiplied what's inside the brackets
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6x + 2x = 40 + 8; do some basic algebra to find x; (added 8 to both sides)
:
8x = 48
:
x = 48/8
:
x = 6 which is the width
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It said that L = 3x - 4, therefore:
L = 3(6) - 4
L = 18 - 4
L = 14; is the length
:
Check our solutions in the perimeter:
2(14) + 2(6) =
28 + 12 = 40</span>
Answer: x=3
Step-by-step explanation:
Took the assignment
Answer:
y=-2x-4
Step-by-step explanation:
6x + 3y=-12 subtract 6x to other side
3y=-12-6x divide 3 to every number
1y=-4-2x
1. My number has two digits.
- 59 is a two-digit number. ✔
2. Double my number is less than 150.
- Double of 59 is 118, which is less than 150. ✔
3. I am not divisible by 12.
- Since 59 is an odd number, hence it is not divisible by 12. ✔
4. My digits are different from each other.
- The digits 5 and 9 are different. ✔
5. The second digit in my number is divisible by an odd number.
- 9 is divisible by an odd number, i.e. 3. ✔
6. My first digit is less than my second digit.
7. My digits add up to 14.
Therefore, the required number is .