It depends on what x is equal to. For example, if x = 3, your equation is 3 * 2 + 1 + 3 - 2 = 8.
Answer:
Step-by-step explanation:
The altitude to the hypotenuse of a right triangle create two smaller triangles, all of which are similar to the original. This means corresponding sides are proportional.
3. Using the above relationship, ...
short-side/hypotenuse = 8/y = y/(8+23)
y^2 = 8·31
y = 2√62
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long-side/hypotenuse = z/(8+23) = 23/z
z^2 = 23·31
z = √713
__
short-side/long-side = 8/x = x/23
x^2 = 8·23
x = 2√46
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4. The picture is fuzzy, but we think the lengths are 25 and 5. If they're something else, use the appropriate numbers. Using the same relations we used for problem 3,
y = √(5·25) = 5√5 . . . . . . . = √(short segment × hypotenuse)
z = √(20·25) = 10√5 . . . . . = √(long segment × hypotenuse)
x = √(5·20) = 10 . . . . . . . . . = √(short segment × long segment)
Answer:
6000 square millimeters
Step-by-step explanation:
Side length of the slanting side can be calculated using the Pythagorean theorem,
L = sqrt(30^2+40^2) = 50
sufrace area of a triangular prism
= surface area of the end sections + the surface area of the three side faces
= 2*(30*40/2) + 40*(30+40+50)
= 1200 + 4800
= 6000 mm^2
Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 
is 
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given
Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.
Substituting m1 we get m2 as
Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line is
2nd, 4th, and 5th answers are correct
