Question

Find the 10th term of a geometric sequence if a1=5 and the common ratio r=2

Answer 1

Answer:

The 10th term of the GP is 2560.

Step-by-step explanation:

It is given that,

The first term of the GP, a = 5

Common ratio, r = 2

We need to find the 10th term of the GP. The nth term of a GP is given by :

$T_n=ar^{n-1}$

Put n = 10

$T_{10}=5\times 2^{10-1}\\\\T_{10}=2560$

So, the 10th term of the GP is 2560.