Select all ratios equivalent to 6:2. 20:1 15:5 21:7 HELP

2.1-?=1 1/2 Please answer this I don’t want to fail

Sveta_85 [38]

.6. This is right, brainliest?

3 0

3 years ago

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Find the surface area of the composite figur

elena-14-01-66 [18.8K]

By definition of surface area and the area formulae for squares and rectangles, the surface area of the composite figure is equal to 166 square centimeters.

<h3>What is the surface area of a composite figure formed by two right prisms?</h3>

According to the image, we have a composite figure formed by two right prisms. The surface area of this figure is the sum of the areas of its faces, represented by squares and rectangles:

A = 2 · (4 cm) · (5 cm) + 2 · (2 cm) · (4 cm) + (2 cm) · (5 cm) + (3 cm) · (5 cm) + (5 cm)² + 4 · (3 cm) · (5 cm)

A = 166 cm²

By definition of surface area and the area formulae for squares and rectangles, the surface area of the composite figure is equal to 166 square centimeters.

To learn more on surface areas: brainly.com/question/2835293

#SPJ1

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bcos%2030%7D%7B1%2Bsin30%7D%3Dtg30" id="TexFormula1" title="\frac{cos 30}{1+sin30}=tg

Kay [80]

$\cos 30=\frac{\sqrt{3}}{2}$

$\sin 30 = \frac{1}{2}$

$\tan 30=\frac{1}{\sqrt{3}}$

Now we insert that into the equation:

$\dfrac{\frac{\sqrt{3}}{2}}{1+\frac{1}{2}} = \frac{1}{\sqrt{3}}$

$\dfrac{\frac{\sqrt{3}}{2}}{\frac{3}{2}} = \frac{1}{\sqrt{3}}$

$\frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}$

$\frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}\\$

$\frac{\sqrt{3}}{3} = \frac{\sqrt{3}}{\sqrt{3}\cdot \sqrt{3}}\\$

$\frac{\sqrt{3}}{3} = \frac{\sqrt{3}}{3}$

6 0

4 years ago

Question 8 of 10

Levart [38]

Answer:

Step-by-step explanation:

Indicates leg lengths of 1 and√3 and hypotenuse 2, the desired ratio is √3/2

8 0

3 years ago

A runner runs around a circular track. He completes one lap at a time of t = 269 s at a constant speed of v = 4.6 m/s. What is t

AURORKA [14]

Answer:

$\boxed{\text{197 m}}$

Step-by-step explanation:

The formula relating distance (d), speed (s), and time (t) is

d = st

1. Calculate the distance

d = 269 s × 4.6 m·s⁻¹ = 1240 m

2.Calculate the track radius

The distance travelled is the circumference of a circle

$\begin{array}{rcl}C & = & 2 \pi r\\1240 & = & 2 \pi r\\\\r & = & \dfrac{1240}{2 \pi }\\\\& = & 197\\\end{array}\\\text{The radius of the track is }\boxed{\textbf{197 m}}$

5 0

4 years ago