Your voltmeter and your teacher are both right, but the water analogy of electricity can only go so far. One big drawback is that, unlike with water, there is no absolute voltage. .... Wherever you put the black lead is defined as "0V". .... flowing (i.e. the circuit is broken) you will not get this change in voltage.
To find the displacement between t=0 and t=1, we want to plug 0 & 1 into the equations, then find the different in the answers.
<u>When t = 0:</u>
x = 4 cos(π(0)+π/4) → π · 0 = 0, so therefore:
x = 4 cos (π/4) → cos (π/4) = √2/2
x = 4 (√2/2)
x = 4√2/2 → 4 divided by 2 = 2, so we can simplify this to
x = 2√2
<u>When t = 1:</u>
x = 4 cos(π(1)+π/4) → π · 1 = π, so therefore:
x = 4 cos (π + π/4) → π + π/4 = 5π/4, so therefore
x = 4 cos (5π/4) → cosine of 5π/4 = -√2/2
x = 4 · -√2/2
x = -4√2/2 → -4 divided by 2 = -2, so we can simplify this to
x = -2√2
<u>Answer</u>: Then, we find the difference between x(0) and x(1), which is x(1)-x(0) =
-√2/2 - √2/2 = <u>-√2</u>
Answer:bars
Explanation: its primary purpose is the control the movement of the back of the hoof
Answer:
D f is even,h and s is odd
