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ss7ja [257]
3 years ago
9

What is X−cel ​Company's net income or net loss if it had Revenue of​ $1,800, Salary Expense of​ $500, Utility Expense of​ $250,

and Withdrawals of​ $5,000 during​ October?
Mathematics
1 answer:
joja [24]3 years ago
5 0
1800 -500 -250  =  1050
the    withdrawal does not count  against income.
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the drama club held a car wash on Saturday and Sunday. they washed a total of 60 cars.if they washed 40% of the cars on subday,h
babymother [125]


60 x 40%

60 x .40 =  24

The drama club washed 24 cars on Sunday.

Hope this helps. :)

5 0
3 years ago
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What is 1365in Egyptian numeral​
anygoal [31]

Answer:

I used an Egyptian numeral converter.

Step-by-step explanation:

8 0
4 years ago
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
Is my answer correct?
Yanka [14]

I would have used graph b. Because it shows the decrease more than graph a.

8 0
3 years ago
Please literally anyone help
Lemur [1.5K]
The measure of the angle is half the measure of the opposite arc.
.. ? = 78°/2 = 39°
7 0
3 years ago
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