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11 months ago

Divide 5 3/4 ÷ 1 1/2

Mathematics

1 answer:

Kipish [7]11 months ago

6 0

The required mixed number is $3\frac{5}{6}$ . The calculations are attached with the solution as an image.

What is a mixed number ?

A bit represented with its quotient and remainder is a mixed bit. For illustration,21/3 is a mixed bit, where 2 is the quotient, 1 is the remainder.
So, a mixed bit is a combination of a whole number and a proper bit. A mixed bit, also called a mixed number, is a whole number and a bit together.
The bit is written to the right of the whole number.
A mixed number is formed by combining three corridor a whole number, a numerator, and a denominator. The numerator and denominator are part of the proper bit that makes the mixed number.

The required mixed number is $3\frac{5}{6}$ . The calculations are attached with the solution as an image.

Learn more about mixed number here:

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A researcher wishes to estimate, with 9090% confidence, the proportion of adults who have high-speed Internet access. Her es

Sunny_sXe [5.5K]

Answer: a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : $z_{\alpha/2}=1.645$

a) Prior estimate of true proportion: p=28%=0.28

Formula to find the sample size :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219$

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

Formula to find the sample size :-

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.645}{0.05})^2\\\\=270.6025\approx271$

Required minimum sample size= 271

8 0

2 years ago

JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the rhombus.

anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

$JL = 48$

$KM = 20$

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

$P = 2\sqrt{(JL)^2 + (KM)^2}$

Substitute values for JL and KM

$P = 2\sqrt{48^2 + 20^2}$

$P = 2\sqrt{2304 +400}$

$P = 2\sqrt{2704}$

$P = 2 * 52$

$P = 104$

Hence, the perimeter is 104 units

5 0

2 years ago

Help,anyone can help me do quetion.

3241004551 [841]

Answer:

(a) x = $128^{o}$

(b) x = $74^{o}$

Step-by-step explanation:

A. sum of angles in a polygon = (n - 2) 180

The polygon given is an irregular pentagon, where n = 5

So that;

sum of angles in a pentagon = (5 - 2) 180

= 3 x 180

= $540^{o}$

Thus,

x + 90 + 76 + 110 + 136 = $540^{o}$

x + 412 = $540^{o}$

x = $540^{o}$ - 412

x = $128^{o}$

B. The polygon given is an irregular pentagon, where n = 5.

Let the supplementary angle with angle 38 be represented by y,

y + 38 = 180

y = 180 - 38

= $142^{o}$

y = $142^{o}$

Let the supplementary angle with x be represented by z, so that;

z + 72 + 120 + 100 + 142 = $540^{o}$

z + 434 = $540^{o}$

z = $540^{o}$ - 434

= $106^{o}$

z = $106^{o}$

But, x + z = $180^{o}$

Then;

x + $106^{o}$ = $180^{o}$

x = $180^{o}$ - $106^{o}$

= $74^{o}$

x = $74^{o}$

7 0

3 years ago

Find an equation of the circle that satisfies the given conditions:

Anna71 [15]

Given the two end of the diameter of the circle, we are able to compute the center of the circle as 0.5*[(-1,3)+(7,-7)]=(3,-2). The radius of the circle is 0.5*sqrt[(-1-7)^2+(3+7)^2]=sqrt(41). Therefore the equation of the circle is (x-3)^2+(y+2)^2=41.

5 0

2 years ago

What is the range of y = sinx in the interval - π ≤ x ≤ 0?

Kaylis [27]

Answer:

$-1 \le y \le 1$

Step-by-step explanation:

Let be $y = \sin x$ , the range of the function corresponds to the set of values of $y$ . The sine function is a bounded function between -1 and 1. Hence, the range of the function is:

$-1 \le y \le 1$

6 0

2 years ago