In a(n) __________ situation, a wireless device is configured to appear to be a legitimate access point, enabling the operator t
1 answer:
You might be interested in
Answer:
Here is the C++ program:
#include <iostream> //to use input output functions
#include<string.h> // to manipulate strings
using namespace std; //to identify objects like cin cout
void ReverseString(char* original_str){ // function that reverses a C-string
char* ptr1 = original_str; // pointer that points to the start of C-string
char* ptr2 = original_str; // pointer that points to the start of C-string initially
for (int i = 0; i < strlen(original_str)- 1; i++) {//iterates through the length of the C-string
ptr2++;} //moves ptr2 to the end of the C-string
while(ptr1 < ptr2) {// swaps each character of C-string using pointers
char temp = *ptr1; //declares a temp variable to hold character that *ptr1 points to
*ptr1 = *ptr2;
*ptr2 = temp;
ptr1++; //increments ptr1 moving it forward
ptr2--; }} //decrements ptr2 moving it backwards
int main(){ //start of main() function
char input_str[]=""; /// declare a C-string
cout<<"Enter original string: "; //prompts user to enter a string
cin>>input_str; // reads that C-string from user
ReverseString(input_str); //calls function to revserse the input string
cout<<"\nReversed string: "<<input_str;} // displays the reversed string
Explanation:
The program has a function ReverseString that takes a C-style string as parameter and reverses the string using pointers.
The ptr1 and ptr2 are pointers that initially point to the beginning of original string.
for (int i = 0; i < strlen(original_str)- 1; i++) this statement has a for loop that iterates through the original string and moves the ptr2 to point at the end or last character of the C-string. strlen() method is used to get the length of the C-string. At each iteration ptr2 moves one time forward until the last character of the C-string is reached.
while(ptr1 < ptr2) statement has a while loop that works as follows:
checks if ptr1 is less than ptr2. This evaluate to true because the index of first character that ptr1 points to is 0 and last character is 5 so 0<5. Hence the statements inside while loop execute which swaps the character of C-string from beginning and end index using ptr1 and ptr2. a temp variable is declated to hold character that *ptr1 points to.
For example
original_string = "xyz" Then temp = *ptr1; stores the character that *ptr1 points to i.e. 'x'
*ptr1 = *ptr2; This statement assigns the character that *ptr2 points to the *ptr1. Basically these pointers are used as indices to the C-string. So this means that the *ptr1 now stores the last character of the C-string that is pointed to by *ptr2. So *ptr1 = 'z'
*ptr2 = temp; This statement assigns the character that temp stores to the *ptr2. We know that temp contains the first character i.e 'x'. So *ptr2 = 'x'
ptr1++; The ptr1 is incremented to 1. This means it moves one position ahead and now points to the second character of the C-string.
ptr2--; The ptr2 is decremented to 1. This means it moves one position backwards and now points to the second character of the C-string.
Now the while loop breaks because ptr1 < ptr2 condition evaluates to false.
So the original string is reversed using pointers. Hence the output is:
zyx
screenshot of the program along with its output is attached.
