All categories

4 years ago

Round 296,386,482 to nearest million

Mathematics

2 answers:

Katen [24]4 years ago

8 0

The real answer is 296,000,000

Bezzdna [24]4 years ago

5 0

The answer is 6 million.

You might be interested in

A person places $82100 in an investment account earning an annual rate of 4.3%, compounded continuously. Using the formula V = P

SVETLANKA909090 [29]

Answer:

$89,472.58

Step-by-step explanation:

P = $82100

r = 4.3% = 4.3/100 = 0.043

T = 2 years

V = P × e^rt

V = 82100 × e^(0.043 × 2)

V = 82100 × e^(0.086)

V = 82100 × 1.0898

V = 89,472.58

The interest after 2 years is $89,472.58

7 0

3 years ago

What is probability? Give an example.

Novosadov [1.4K]

Answer:

just another way to say problem

Step-by-step explanation:

8 0

3 years ago

What is the percentage of 56 in 70

avanturin [10]

Answer:

Step-by-step explanation:

5 0

3 years ago

It takes a smaller hose 4 times as long to fill a certain swimming pool as it does a larger hose. It take both hoses working tog

faust18 [17]

Answer:

Larger hose will take 18 minutes and 45 seconds

Step-by-step explanation:

ONE smaller hose fills the pool in 5*15 = 75 minutes.One large hose can do this job in 75/4 minutes = 18 3/4 minutes = 18 minutes and 45 seconds

4 0

3 years ago

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2. The numbers of

klio [65]

Answer:

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2

Three weeks, so $\mu = 2*3 = 6$

Calculate the probability that fewer than four tornadoes occur in a three-week period.

This is:

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.0025$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.0149$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.0446$

$P(X = 3) = \frac{e^{-6}*6^{3}}{(3)!} = 0.0892$

Then

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0025 + 0.0149 + 0.0446 + 0.0892 = 0.1512$

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

7 0

3 years ago