Answer:
arc PST = 254°
Step-by-step explanation:
arc QPT = 180° because it is a diameter
arc PQ = 74°
arc PT = 180° - 74° = 106°
arc PST = 360° - 106° = 254°
Subtract 10 and collect terms to get the variable term by itself on the left.
... 4c = 24
Divide by the coefficient of the variable, 4.
... c = 6
The appropriate choice is the second one:
... 6
_____
You don't actually have to sove the equation to find the right answer. You just need to see which answer works.
-6: 5(-6) -(-6) +10 = -14 ≠ 34
6: 5(6) -(6) +10 = 34 . . . . . . . this answer works (you can stop here)
11: 5(11) -(11) +10 = 54 ≠ 34
-11: 5(-11) -(-11) +10 = -34 ≠ 34
Answer:
7/55 or 12.727272727273%
Step-by-step explanation:
7/55 or 12.727272727273%
7 big and pink
so 7/?
?= amount of bows
and them up and you get 55
7/55
Answer:
Ty for the free points lol
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
