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3 years ago

What is 60% out of 20

Mathematics

2 answers:

zhannawk [14.2K]3 years ago

6 0

It is 20% because it is 20 out of 60%

elena55 [62]3 years ago

4 0

I hope this helps you out

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If L

BabaBlast [244]

Pythagorean's theorem says the hypotenuse of a triangle is A^2+B^2=C^2 in this case I'll put the L,W, and D so it's easy to understand. L^2+W^2=D^2 is the exact same formula as above and is how we will solve this. (30^2)+(10^2)=1000 then we take the square root since 1000=D^2, and we get 36.62 as D.

3 0

3 years ago

What is 5/4 of a right angle

natka813 [3]

A right angle is 90 degrees
So you 90/4=22.5
Then 90+22.5=112.5
Hope this helped!

6 0

2 years ago

In a normal distribution, what is the probability that a randomly selected data value will fall within two standard deviations o

Zepler [3.9K]

The answer is 95%

This is something you should memorize. Specifically it is from the Empirical Rule (or 68-95-99.7 rule) which gives rough approximations of areas under the curve.

5 0

3 years ago

What is the minimum y-value after which the exponential function will always be greater than the linear function? y = 1 y = 2 y

Alenkinab [10]

From the graph we can see that in the interval [0,1] the value of y is less than 1.

In the interval [1,2] the value of y value is 2 to 4.

In the interval [2,infinity) the graph is going up, and the value of y is greater than or equal to 4.

Therefore, the graph going up after y=4 above the line.

Therefore, the minimum y-value is 4 after which the exponential function will always be greater than the linear function.

8 0

3 years ago

Read 2 more answers

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

3 years ago