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2 years ago

Juan always saves the same amount from his weekly allowance. The table shows how much he has saved at different times.

Mathematics

2 answers:

Gnesinka [82]2 years ago

8 0

Y + 46 = 3(x – 12)
<span>I'm pretty sure it's B. this is so long question</span>

mezya [45]2 years ago

6 0

You're correct, it is B. If you plug in 3 (weeks) in for "x" and 19 (amount saved) for "y" you will get 0=0, which is a solution.

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Find the equation of the regression line and the value of the correlation coefficient (r).

tino4ka555 [31]

Answer:

According with the graph:

1.) The equation of the regresion line is: y=5,720.10391 x + 957.225810

2.) The values of the correlation coefficient is 0.86

Step-by-step explanation:

In the graph is shown:

1.) Line of Best Fit

y=5720.10391 x + 957.225810

2.) Correlation

.86

3 0

2 years ago

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$