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3 years ago

Juan always saves the same amount from his weekly allowance. The table shows how much he has saved at different times.

Mathematics

2 answers:

Gnesinka [82]3 years ago

8 0

Y + 46 = 3(x – 12)
I'm pretty sure it's B. this is so long question

mezya [45]3 years ago

6 0

You're correct, it is B. If you plug in 3 (weeks) in for "x" and 19 (amount saved) for "y" you will get 0=0, which is a solution.

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Can someone help me with this

kotegsom [21]

First you have to find out how old ben is
then times it by 3

Use algebra to figure out the answer

i am telling you this because i don't know the answer

5 0

3 years ago

Read 2 more answers

A line passes through the points (4,6) and (6,2) .

siniylev [52]

ANSWER

Yes

No

No

Yes

EXPLANATION

The given line passes through the points,.
$(4,6) \: and \: (6,2)$

We need to determine the slope of this line using these two points.

The formula for finding the slope is

$m=\frac{y_2-y_1}{x_2-x_1}$

$m = \frac{2 - 6}{6 - 4} = - \frac{ - 4}{2} = - 2$

We can now use the formula

$y-y_1=m(x-x_1)$
in the slope intercept form.

If we use the point
$(4,6)$
the equation will be,

$y - 6 = - 2(x - 4)$

If we use the point,

$(6,2)$
we obtain,
$y - 2 = - 2(x - 6)$

6 0

3 years ago

Read 2 more answers

The perimeter of a triangle is 510 feet and the sides are in the ratio of 11:16:24. Find the area of the triangle

Nutka1998 [239]

If the sides are in the ratio of 11:16:24, it means that they are all multiples of a same number x, according to these factors.

So, the shorter side is 11x feet long, the middle one is 16x feet long, and the longest side is 24x feet long.

This means that the perimeter is

$11x+16x+24x = 51x$ feet long. But we know that this is 510 feet, so we have

$51x = 510 \implies x = \cfrac{510}{51} = 10$ .

So, the three sides are 110, 160 and 240 feet long.

To find the area of a triangle knowing its three sides, you can use Heron's formula, which states that, if $s$ is half the perimeter of the triangle whose sides are $a,b,c$ , the area $A$ is given by

$A = \sqrt{s(s-a)(s-b)(s-c)}$

In our case, $s = 255, a = 110, b = 160, c = 240$ so the formula becomes

$A = \sqrt{255(255-110)(255-160)(255-240)} = \sqrt{255(145)(95)(15)} = \sqrt{52689375} \approx 7258.74$

5 0

4 years ago

16. Peter works part time for 3 hours every day and Cindy works part time for 2 hours every day.

Ber [7]

Answer:

Part A)

4.50 × 3 > 4.50 × 2
13.5 0 > 9

Part B)

r ≥ 7

Explanation:

1) The earnings are calculated multiplying the number of hours by the hourly rate.

2) The hourly rate of both Peter and Cindy is the same: $ 4.50 / hour

3) Let the variable used for computing the number of hours be h.

4) The number of hours Peter works every day is 3 hours, so, using the letter P to name Peter's earnings, the expression to calculate his earnings is:

P = 4.50 × 3

5) Similarly, the expression to calculate Cindy's earnings would be:

C = 4.50 × 2

Answering part A)

You have to write an inequality to compare Peter's and Cindy's earnings:

4.50 × 3 > 4.50 × 2
13.5 0 > 9

This is, the earnings of Peter are greater than the earnings of Cindy.

Part B),

You have to write an inequality to calculate Cindy's per-hour income so that she earns at least $ 14 a day.

Here, C ≥ 14, because the sign ≥ means greater than or equal to, meaning the the earnings are greater than or equal to 14.

Thus, since she works 2 hours per day, the inequality becomes 2 × r ≥ $ 14, where r is the per-hour income.

To solve it follow these steps:

Given: 2r ≥ 14

Divide both sides by 2: r ≥ 14 / 2

Simplify: r ≥ 7

That means that Cindy's per-hour income should be at least $7 and hour so that she earns $14 a day.

7 0

3 years ago

What is the perimeter of a triangle with vertices of (5,1) (-3,3) (-7,-3)

timurjin [86]

$Vertices:\\
A(5,1)\\B(-3,3)\\C(-7,-3)\\\\ You\ must\ find\ length\ of\ AB,\ BC,\ AC.\\\\
A(5,1)\ \ \ \ \ \ B(-3,3)\\\\Distance\ between\ A \ and\ B:\\AB=\sqrt{(x_B-x_A)^2+(y_A-y_B)^2}\\\\AB=\sqrt{(-3-5)^2+(3-1)^2}\\AB=\sqrt{8^2+2^2}\\AB=\sqrt{64+4}\\AB=\sqrt{68}
$ $
 B(-3,3)\ \ \ \ C(-7,-3)\\\\Distance\ between\ B \ and\ C:\\BC=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}\\\\BC=\sqrt{(-7-(-3))^2+(-3-3)^2}\\BC=\sqrt{(-4)^2+(-6)^2}\\BC=\sqrt{16+36}\\BC=\sqrt{52}$ $A(5,1)\ \ \ \ \ \ C(-7,-3)\\\\Distance\ between\ A \ and\ C:\\AC=\sqrt{(x_C-x_A)^2+(y_C-y_A)^2}\\\\AC=\sqrt{(-7-5)^2+(-3-1)^2}\\AC=\sqrt{(-12)^2+(-4)^2}\\AC=\sqrt{144+16}\\AC=\sqrt{160}$ $Perimeter\ of\ triangle=\ AB+AC+BC=\\\sqrt{68}+\sqrt{52}+\sqrt{160}=2\sqrt{17}+2\sqrt{13}+2\sqrt{40}$

5 0

3 years ago