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Elina [12.6K]
3 years ago
12

What is the focus of a parabola with equation y^2=4x

Mathematics
2 answers:
givi [52]3 years ago
5 0
Vertex: <span><span>(0,0)</span><span>(0,0)</span></span>Focus: <span><span>(1,0)</span><span>(1,0)</span></span>Axis of Symmetry: <span><span>y=0</span><span>y=0</span></span>Directrix: <span>x=−<span>1</span></span>
dem82 [27]3 years ago
3 0

Answer:

Focus = (1,0)

Step-by-step explanation:

The equation of parabola with vertex at origin is given by:

y^2 = 4ax           ....[1]

where, 4a is the width of the parabola and a is positive.

Focus = (a, 0)

Given the equation:

y^2=4x on comparing with [1] we have;

4a = 4

Divide both sides by 4 we have;

a = 1

Focus = (1, 0)

Therefore, the focus of a parabola with equation is, (1, 0)

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