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Elina [12.6K]
3 years ago
12

What is the focus of a parabola with equation y^2=4x

Mathematics
2 answers:
givi [52]3 years ago
5 0
Vertex: <span><span>(0,0)</span><span>(0,0)</span></span>Focus: <span><span>(1,0)</span><span>(1,0)</span></span>Axis of Symmetry: <span><span>y=0</span><span>y=0</span></span>Directrix: <span>x=−<span>1</span></span>
dem82 [27]3 years ago
3 0

Answer:

Focus = (1,0)

Step-by-step explanation:

The equation of parabola with vertex at origin is given by:

y^2 = 4ax           ....[1]

where, 4a is the width of the parabola and a is positive.

Focus = (a, 0)

Given the equation:

y^2=4x on comparing with [1] we have;

4a = 4

Divide both sides by 4 we have;

a = 1

Focus = (1, 0)

Therefore, the focus of a parabola with equation is, (1, 0)

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Answer:

A real number

Step-by-step explanation:

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Inga [223]

Answer:

-26,-24,-22

Step-by-step explanation:

<em><u>The correct question is</u></em>

The sum of three consecutive even integers is -72. what are the three numbers

Let

x ----> the first consecutive even integer

x+2 ----> the second consecutive even integer

x+4 ----> the third consecutive even integer

we know that

x+(x+2)+(x+4)=-72

solve for x

3x+6=-72\\3x=-78\\x=-26

so

x+2=-26+2=-24

x+4=-26+4=-22

therefore

the numbers are

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3 years ago
Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
Verdich [7]

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

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x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

8 0
3 years ago
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