Complete question :
A data set includes data from student evaluations of courses. The summary statistics are nequals92, x overbarequals4.09, sequals0.55. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Answer:
H0 : μ = 4.25
H1 : μ < 4.25
T = - 2.79
Pvalue =0.0026354
we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%
Step-by-step explanation:
Given :
n = 92, xbar = 4.09, s = 0.55 ; μ = 4.25
H0 : μ = 4.25
H1 : μ < 4.25
The test statistic :
T = (xbar - μ) ÷ s / √n
T = (4.09 - 4.25) ÷ 0.55/√92
T = - 0.16 / 0.0573414
T = - 2.79
The Pvalue can be obtained from the test statistic, using the Pvalue calculator
Pvalue : (Z < - 2.79) = 0.0026354
Pvalue < α ; Hence, we reject the Null
Thus, we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%
Answer:
i) Assigning women at random ensures that the two groups are comparable.
iv) A control group provides a baseline for comparisons to determine treatment effects.
Step-by-step explanation:
(a)
It is pertinent that there two comparable groups. In light of the fact that it will help in making better decisions since there will be some people who have blood pressure as a result of uncontrolled physical characteristics such as anger, positive attitude, lower blood pressure. etc Thus, there is a need to consider two equivalent groups.
(b)
A control group is used as a benchmark for determining the cause and effect of a treatment on a given experimental group. This may be in regard to the social aspect of meeting other individuals involved that make up the physical changes.
Answer:
2.943
Step-by-step explanation:
2.943/2.7=1.09
Answer:
y = -2x + 8
Step-by-step explanation:
When two points are given, the equation of the line passing through the points is given by:
where: 
and 
are the two points passing through the line.
Here, 
and 
.
Substituting in the formula, we have:
⇒ 
⇒ y - 4 = -2x + 4
⇒ y = -2x + 8 is the required equation of the line.
Using the Poisson distribution, the probabilities are given as follows:
A. 0.0888 = 8.88%.
B. 0.1354 = 13.54%.
C. 0.8646 = 86.46%.
<h3>What is the Poisson distribution?</h3>
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:
The parameters are:
- x is the number of successes
- e = 2.71828 is the Euler number
is the mean in the given interval.
Item a:
10 hours, 2 calls per hour, hence the mean is given by:
.
The probability is P(X = 20), hence:
Item b:
1 hour, hence the mean is given by:
The probability is P(X = 0), hence:
Item c:
The probability is:
More can be learned about the Poisson distribution at brainly.com/question/13971530
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