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kotegsom [21]
3 years ago
10

Here is another math question 6/3+(-1/3)

Mathematics
1 answer:
gtnhenbr [62]3 years ago
6 0
<span>6/3+(-1/3)
</span><span>= 6/3-1/3
= 5/3
= 1 2/3</span>
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If you start with Malvin’s age, take half of it, increase that result by 5, then divide by 3, and finally double that, you get 8
Kisachek [45]

Answer:

24 years old

Step-by-step explanation:

Let Malvin's age be x.

  • x / 2
  • x / 2 + 5 = 5x / 10  [ By taking the L.C.M.]
  • ( 5x / 10 ) * ( 1 / 3 ) = 5x / 30   [ Multiply with the reciprocal of 3 ]
  • ( 5x / 30 ) * 2 = 5x / 15

Now let's solve the equation,

5x / 15 = 8

       5x = 8 * 15

       5x = 120

         x = 120 / 5

         x = 24

Therefore, Malvin is 24 years old.

Hope yo liked the answer!!

If you found it helpful, please mark it as the Brainliest!!

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2 years ago
Explorers on a planet with a thin atmosphere want to measure the acceleration of gravity at its surface. So they use a spring gu
Murljashka [212]

Answer:

The value of g_s is g_s=\frac{30}{21} \:\frac{m}{s^2}.

Step-by-step explanation:

We know that the position function is given by

s(t)=30t-\frac{g_s}{2} t^2

Velocity is defined as the rate of change of position. Therefore,

v(t)=\frac{d}{dt}(s(t))

So, the velocity function is

v(t)=\frac{d}{dt}(s(t))\\\\v(t)=\frac{d}{dt}(30t-\frac{g_s}{2} t^2)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(30t\right)-\frac{d}{dt}\left(\frac{g_s}{2}t^2\right)\\\\v(t)=30-g_st

When a body reaches a vertical velocity of zero, this is the maximum height of the body and then gravity will take over and accelerate the object downward. Thus,

v(t)=30-g_st=0\\\\g_s=\frac{30}{t}

We know that the ball bearing reaches its maximum height 21 seconds after being launched (t = 21 s).

So, the value of g_s is g_s=\frac{30}{21} \:\frac{m}{s^2}.

5 0
3 years ago
Simplify the expression: 4x(x2 + 6x - 1) will mark brainliest pls help&lt;3​
Rufina [12.5K]
I think it’s 4x3 + 24x2 - 4x
3 0
2 years ago
Read 2 more answers
Amanda needs to make a garden plot which has an area less than 18 sq. feet. The length should be 3 feet longer than the width. W
SCORPION-xisa [38]

Answer:

<em>Any width less than 3 feet</em>

Step-by-step explanation:

<u>Inequalities</u>

The garden plot will have an area of less than 18 square feet. If L is the length of the garden plot and W is the width, the area is calculated by:

A = L.W

The first condition can be written as follows:

LW < 18

The length should be 3 feet longer than the width, thus:

L = W + 3

Substituting in the inequality:

(W + 3)W < 18

Operating and rearranging:

W^2 + 3W - 18 < 0

Factoring:

(W-3)(W+6)<0

Since W must be positive, the only restriction comes from:

W - 3 < 0

Or, equivalently:

W < 3

Since:

L = W + 3

W = L - 3

This means:

L - 3 < 3

L < 6

The width should be less than 3 feet and therefore the length will be less than 6 feet.

If the measures are whole numbers, the possible dimensions of the garden plot are:

W = 1 ft, L = 4 ft

W = 2 ft, L = 5 ft

Another solution would be (for non-integer numbers):

W = 2.5 ft, L = 5.5 ft

There are infinitely many possible combinations for W and L as real numbers.

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2 years ago
4. Two families went camping. The Becker family was 4 miles west of the campsite lake. The Dunn family
tresset_1 [31]

They were 1 mile away from each other.

4-3=1 mile

8 0
3 years ago
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