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sukhopar [10]
3 years ago
14

Curtis paid $80 on the vet bill for his dog. Then the vet charged him $40 more for his dog's medicine. If he now owes the vet $1

20, what was his starting balance?
Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

He paid 80 at the start, so his starting must have been 80

Step-by-step explanation:

80+40=120...

so either 0, or 80 because he owed nothing, or he owed the 80, then the 40 for medication

I hope this helps!

nadya68 [22]3 years ago
6 0

Answer:

Either $200 or $80 depending on the question.

Step-by-step explanation:

1. Curtis paid <em>$80</em>

2. The vet charged <em>$40 </em>for the medicine. <em> x + $40 = $120</em>

3. If he owes the vet <em>$120 </em> and he paid <em>$80 </em>then his total bill is <em>$200.</em>

HOWEVER, if the question is asking what ammount he initially started with it would be <em>$80</em> because that's all he has paid.

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3 years ago
Bill is 2 years older than his brother Will. If the product of their ages is one less than five times the sum of their ages, how
Advocard [28]

Answer:

Will's age = 9 years

Bill's age = 11years

Step-by-step explanation:

Let will age = x

Bill = x +2 since he is 2 years older

x(x+2) = 5( x +x+2) - 1

Opening brackets

x² + 2x = 5(2x + 2) - 1

x² + 2x = 10x + 10 - 1

x² + 2x = 10x + 9

Collect like terms

x² + 2x - 10x - 9 = 0

x² - 8x - 9 = 0

Solve quadratically using factorisation method by finding two factors of +9 that can add up to give -8, the coefficient of x.

The factors are -9 and +1

x² + x - 9x - 9 = 0

x(x + 1) -9( x +1)

x+1) (x -9) =0

x + 1 = 0 or x -9 =0

x = -1 or 9

Age can not be negative

Therefore,

Will's age = 9 years

Bill's age = x+2 = 9+2 = 11years

I hope this was helpful, please rate as brainliest

6 0
3 years ago
Draw a diagram that represents 4/5
o-na [289]
Here I drew one to show an example
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4 0
3 years ago
For the following pair of functions, find (f+g)(x) and (f-g)(x).
ch4aika [34]

Given:

The functions are

f(x)=4x^2+7x-5

g(x)=-9x^2+4x-13

To find:

The functions (f+g)(x) and (f-g)(x).

Solution:

We know that,

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x^2+7x-5-9x^2+4x-13

(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)

(f+g)(x)=-5x^2+11x-18

And,

(f-g)(x)=f(x)-g(x)

(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)

(f+g)(x)=4x^2+7x-5+9x^2-4x+13

(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)

(f-g)(x)=13x^2+3x+8

Therefore, the required functions are (f+g)(x)=-5x^2+11x-18

and (f-g)(x)=13x^2+3x+8.

7 0
3 years ago
300 ml over 15 min is what rate of ml per hour
Mama L [17]

Answer:

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Step-by-step explanation:

To compute what rate is 300 ml over 15 mins as a rate of ml per hour, we do a rule of 3, using a variable x as that amount of ml we don't know yet. We should have everything in the same units, so instead of writing 1 hour we write 60 minutes:

\frac{300~ml}{15~min}=\frac{x~ml}{60~mins}

Now we solve for x:

\frac{300~ml}{15~min}\cdot 60~mins=x~ml

\frac{18000~ml}{15} =x~ml

1200~ml =x~ml

And so, now that we know the value of x, the rate we wanted to find is

\frac{1200~ml}{60~mins}

Which is just 1200 ml per hour.

3 0
3 years ago
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