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strojnjashka [21]

3 years ago

5

Which graph represents the division of -12 / 4 ?

1 answer:

IRISSAK [1]3 years ago

3 0

The top graph represents the division of -12/4

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Suppose P(E) = 81%; P(E and F) = 9%; and P(E or F) = 65%,

PIT_PIT [208]

Using Venn probabilities, it is found that P(F) = -0.07, which is not a probability, as it is a negative value.

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We have two events, E and F.
Their probabilities are: $P(E) = 0.81, P(E \cap F) = 0.09, P(E \cup F) = 0.65$
The probabilities are related by the following equation:

$P(E \cap F) = P(E) + P(F) - P(E \cup F)$

Replacing into the equation, we can find P(F).

$0.09 = 0.81 + P(F) - 0.65$

$0.16 + P(F) = 0.09$

$P(F) = -0.07$

P(F) = -0.07, which is not a probability, as it is a negative value.

A similar problem is given at brainly.com/question/21421475

4 0

2 years ago

Simplify the expression.<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B%5Csqrt%7B3%7D-2%20%7D" id="TexFormula1" tit

zhannawk [14.2K]

Answer:

I have attached the work to your problem.

Please see the attachment below.

I hope this helps!

7 0

2 years ago

What is the range of the function y=3/x+8?

myrzilka [38]

The domain of the function is (-∞, -8) and (-8, ∞). Then the range of the function will be (-∞, 0) and (0, ∞).

<h3>What are domain and range?</h3>

The domain means all the possible values of the x and the range means all the possible values of the y.

The function is given below.

y = 3/(x + 8)

Then the domain of the function is (-∞, -8) and (-8, ∞). Then the range of the function will be (-∞, 0) and (0, ∞).

More about the domain and range link is given below.

brainly.com/question/12208715

#SPJ1

3 0

1 year ago

Find the length od ypx. Leave your answer in terms of pi

Liono4ka [1.6K]

your answer is

b = 15 pi

length of ypx = circumfrance of circle - 1/4 of circumfrance of circle

= 2pi r - 2pi r/4 = 6 pi r / 4 = 3 pi r / 2

= 3 pi × 10/2 = 15 pi

5 0

2 years ago

Read 2 more answers

Х- а<br>x-b<br>If f(x) = b.x-a÷b-a + a.x-b÷a - b<br>Prove that: f (a) + f(b) = f (a + b)

GenaCL600 [577]

Given:

Consider the given function:

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}$

To prove:

$f(a)+f(b)=f(a+b)$

Solution:

We have,

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}$

Substituting $x=a$ , we get

$f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}$

$f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}$

$f(a)=0+a$

$f(a)=a$

Substituting $x=b$ , we get

$f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}$

$f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}$

$f(b)=b+0$

$f(b)=b$

Substituting $x=a+b$ , we get

$f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}$

$f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}$

$f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}$

$f(a+b)=\dfrac{b^2-a^2}{b-a}$

Using the algebraic formula, we get

$f(a+b)=\dfrac{(b-a)(b+a)}{b-a}$ $[\because b^2-a^2=(b-a)(b+a)]$

$f(a+b)=b+a$

$f(a+b)=a+b$ [Commutative property of addition]

Now,

$LHS=f(a)+f(b)$

$LHS=a+b$

$LHS=f(a+b)$

$LHS=RHS$

Hence proved.

5 0

2 years ago