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3 years ago

The sum of 2 numbers is 55 and the difference is 1. what are the numbers

1 answer:

7 0

First no. = x
Second no. = y

Equation Formation
x + y = 55..........equation (i)
x - y = 1..............equation (i)

x = 1+y

1 + y + y = 55
1 + 2 y = 55
2 y = 55-1
2 y = 54
y = 27

x=27 + 1
x =28

Answer = 28 , 27

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Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

Can someone please help me with this question.ASAP

expeople1 [14]

Sorry don't know the answer

8 0

3 years ago

Find the slope of the line passing through the points(3,-9) and(2,-2) .

tino4ka555 [31]

Answer:

-7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-(-9))/(2-3)

m=(-2+9)/-1

m=7/-1

m=-7

5 0

3 years ago

What is the length of x? What is the length of EF? Only enter numbers in the answer boxes below:

ioda

Focus on triangles DFC and DFE:

They are both right triangles because DF is perpendicular to EC

DC=DE

DF is a common side

So, the two triangles are congruent. It follows that CF=FE, and in particular

$8x=3x+15 \iff 5x=15 \iff x=3$

And since x=3, the length of EF is

$3x+15=3\cdot 3+15=24$

8 0

4 years ago

75% of the apple pies are sold on Tuesday and the remainder with thrown out if 12 apple pies were sold on Tuesday then how many

sashaice [31]

Answer:

75 % of 12 = (75 * 12 ) / 100 = 9 were sold

12 - 9 = 3 were thrown out

Step-by-step explanation:

6 0

3 years ago