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2 years ago

Find the slope of the line passing through the points(3,-9) and(2,-2) .

Mathematics

1 answer:

tino4ka555 [31]2 years ago

5 0

Answer:

-7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-(-9))/(2-3)

m=(-2+9)/-1

m=7/-1

m=-7

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Two geometrically similar jugs have volumes of 1000 cm3and 512 cm3.They have circular bases. The diameter of the base of the lar

Aleks [24]

Complete Question

Two geometrically similar jugs have volumes of 1000 cm³and 512 cm³.They have circular bases. The diameter of the base of the larger jug is 9 cm.

Calculate the diameter of the smaller jug.

Answer:

7.2 cm

Step-by-step explanation:

To solve the above question,we have the proportion

Smaller volume/ Larger volume = (Smaller diameter/ Larger diameter)³

We are to find the smaller diameter

Hence our formula is give as

Cube root(Smaller volume/ Larger volume)= Smaller diameter/ Larger diameter

=cube root( 512/1000) = x/9

= 8/10 = x/9

Cross Multiply

10x = 8 × 9

10x = 72

x = 72/10

x = 7.2cm

Therefore, the diameter of the second jug is 7.2 cm

3 0

3 years ago

Convert y=2x-5 to slope intercept form

Sonbull [250]

Answer:

y = 2x - 5

Step-by-step explanation:

y = 2x - 5 is in the form

y = mx + b

which is the slope-intercept form.

3 0

2 years ago

Read 2 more answers

Write as a decimal 23/9

Slav-nsk [51]

Answer:

2.555555555555.....

(the 5 is repeating)

Step-by-step explanation:

This is the answer because:

1) To convert the fraction to a decimal, you have to divide the numerator by the denominator.

2) Therefore, 23/9 is 2.5 (the 5 is repeating)

Hope this helps!

8 0

3 years ago

From the start of a trail to the bird lookout point is 3 7/8 mile. From the bird lookout point to the end of the trail is anothe

Juli2301 [7.4K]

Answer:

Distance of the trail from the start to the end is $6\frac{17}{24}$ miles

Step-by-step explanation:

Distance from the start of a trail to the bird lookout point= $3\frac{7}{8}$ miles

Distance from the bird lookout point to the end of the trail = $2\frac{5}{6}$ miles

We want to find the difference of the trail from the start to the end, that is, how far is the starting point from the end point.

The distance between the start and end points

$=3\frac{7}{8}+2\frac{5}{6}\\=\frac{31}{8} +\frac{17}{6}$

$=\frac{161}{24} =6\frac{17}{24}$ miles

3 0

2 years ago

What is the remainder of (4x2 + 7x-1)= (4 + x)?<br>A. -9x – 1<br>B.23x – 1<br>C.35<br>D.-37

bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

$x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\$

Step-by-step explanation:

$\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}$

$\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\$

$\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}$

6 0

2 years ago

Read 2 more answers