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iren [92.7K]
3 years ago
15

Suppose that many large samples were taken from population A, which is normally distributed, and population c, which is not norm

ally distributed. The means of the samples of which of the following populations would approximate a normal distribution?
a. both population a and population c
b. neither
c. population c
d. population a
Mathematics
2 answers:
Murljashka [212]3 years ago
6 0

Answer:

Both populations -Apex

Step-by-step explanation:

OLEGan [10]3 years ago
4 0

Answer:

Population A

Step-by-step explanation:

Think about. If population A already known for normally distribution AND you take large samples. The rest would still be distributed, Which keeps population A a Normal Distribution.

but Population C is nor normally distributed, so if you take away large samples. it will deteriorate its distribution so it won't get any better or in this case, normal. so. it is Population A.

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Find the value of k such that lim-->4 (x^2+x-k)/(x-4) exists
7nadin3 [17]

Answer:

k=20

Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20

6 0
2 years ago
What is <br><br> 88x3-7+198-34x15+76-126=
PilotLPTM [1.2K]

-105

Multiply first, then subtract, then add.

6 0
2 years ago
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A television transmitter tower is 400 feet high. if the angle between the guy wire (attached at the top) and the tower is 51.8°,
vova2212 [387]
Let the length of the guy wire be x feet.
cos 51.8 = 400/x
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8 0
3 years ago
Of all the soft drink consumers in a particular sales region, 30% prefer Brand A and 70% prefer Brand
victus00 [196]

Answer:

Option D -0.67

Step-by-step explanation:

Given : Preference of Brand A =30% ⇒ P(A)=\frac{30}{100}=0.3

Preference of Brand B =70% ⇒ P(B)=\frac{70}{100}=0.7

Prefer Brand A and are Female = 20% ⇒ P(A/F)=\frac{20}{100}=0.2

Prefer Brand B and are Female = 40% ⇒ P(B/F)=\frac{40}{100}=0.4

To find : Selected consumer is female, given that the person prefers Brand A P(F/A)

Solution : Using Bayes' theorem, which state that

P(A/B)=\frac{P(B/A)P(A)}{P(B)}

where, P(A) and P(B) are probabilities of observing A and B.

P(B/A)= is a conditional probability where event B occur and A is true

P(A/B)= also a conditional probability where event A occur and B is true.

Now, applying Bayes' theorem,

P(F/A)=\frac{P(A/F)P(A)}{P(B)P(B/F)+P(A)P(A/F)}

P(F/A)=\frac{(0.2)(0.3)}{(0.7)(0.4)+(0.3)(0.2)}

P(F/A)=\frac{0.6}{0.28+0.6}

P(F/A)=\frac{0.6}{0.88}

P(F/A)=0.68

Therefore, Option D is correct probability that a randomly selected consumer is female, given that the person prefers Brand A -0.67

3 0
3 years ago
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snow_lady [41]

1/64

2^3 = 8

8^-2 = 1/64

5 0
3 years ago
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