If by "long leg lengths" you mean the hypotenuse then the area is 116 sq. units. If you mean the bases of the triangles then the area is 170 sq. units.
If the length of 12 is the hypotenuse, we first must find the base of the triangles using the Pythagorean theorem:
10² + b² = 12²
100 + b² = 144
b² = 44
b = √44 = 6.6
This means we have two triangles and a rectangle. The area of the rectangle is 5(10) = 50 sq. units. The area of each triangle is 1/2(6.6)(10) = 33. Adding all 3 together we have:
50+33+33 = 116 sq. units.
If the 12 is the base, then we have the rectangle with the area of 5(10) = 50 and two triangles each with an area of 1/2(12)(10) = 60:
50+60+60 = 170 sq. units.
Preeeeetty sure it's just 16 for that.
Are you sure you submitted the whole problem?
Answer:
x=53
y=26
H=106
G=93
Step-by-step explanation:
By the inscribed quadrilateral conjecture:
Hope this helps!
Answer:3/35
Step-by-step explanation:
