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umka2103 [35]
3 years ago
10

A board game has a spinner divided into sections of equal size. Each section is labeled with a number between 1 and 5. What is a

reasonable estimate of the number of times the spinner will land on a section labeled 5 over the course of 150 spins
Mathematics
1 answer:
timurjin [86]3 years ago
6 0

Answer:

From the choices given, the most reasonable estimate is 25.

Step-by-step explanation:

5 sections on the spinner means there is a 1/5 chance of landing on any of the sections each spin.

This means landing on a section labeled 5 should happen 1/5(150) = 30 times.  The closest option to this is 25.

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Solution:

(x+1)(2x-4)(\frac{1}{x}+1)=(x+1)(2x-4)(1-\frac{5}{2x}-4)\\(x+1)(2x-4)(\frac{1}{x}+1)-(x+1)(2x-4)(1-\frac{5}{2x}-4) = 0\\(x+1)(2x-4)(\frac{1}{x}+1-(1-\frac{5}{2x}-4))=0\\(x+1)(2x-4)(\frac{1}{x}+1-(-3\frac{5}{2x}))=0\\(x+1)(2x-4)(\frac{1}{x}+1+3+\frac{5}{2x})=0\\(x+1)(2x-4)(\frac{1}{x}+4+\frac{5}{2x})=0\\(x+1)(2x-4)(\frac{5x^{2}+8x+2}{2x} )=0\\

x+1=0\\x=-1\\\\2x-4=0\\x=2\\\\\frac{5x^{2}+8x+2}{2x}=0\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}

Answer:

x=-1\\x=2\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}

<em>Hope this was helpful.</em>

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Answer:

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