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N76 [4]
3 years ago
14

(x+1)(2x-4)(1/x+1) = (x+1)(2x-4)(1-5/2x-4)

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0

Solution:

(x+1)(2x-4)(\frac{1}{x}+1)=(x+1)(2x-4)(1-\frac{5}{2x}-4)\\(x+1)(2x-4)(\frac{1}{x}+1)-(x+1)(2x-4)(1-\frac{5}{2x}-4) = 0\\(x+1)(2x-4)(\frac{1}{x}+1-(1-\frac{5}{2x}-4))=0\\(x+1)(2x-4)(\frac{1}{x}+1-(-3\frac{5}{2x}))=0\\(x+1)(2x-4)(\frac{1}{x}+1+3+\frac{5}{2x})=0\\(x+1)(2x-4)(\frac{1}{x}+4+\frac{5}{2x})=0\\(x+1)(2x-4)(\frac{5x^{2}+8x+2}{2x} )=0\\

x+1=0\\x=-1\\\\2x-4=0\\x=2\\\\\frac{5x^{2}+8x+2}{2x}=0\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}

Answer:

x=-1\\x=2\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}

<em>Hope this was helpful.</em>

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guapka [62]
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7 0
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In a simple regression analysis (where y is a dependent and x an independent variable), if the y-intercept is positive, then it
Rom4ik [11]

Answer:

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

\bar x= \frac{\sum x_i}{n}  

\bar y= \frac{\sum y_i}{n}  

And we can find the intercept using this:  

b=\bar y -m \bar x  

On this case the correct answer would be:

E.  none of the above

Since the intercept has no association between the increase/decrease of the dependent variable respect to the independent variable

Step-by-step explanation:

Assuming the following options:

A.  there is a positive correlation between X and Y

B.  there is a negative correlation between X and Y

C.  if X is increased, Y must also increase

D.  if Y is increased, X must also increase

E.  none of the above

If we want a model y = mx +b where m represent the lope and b the intercept

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

\bar x= \frac{\sum x_i}{n}  

\bar y= \frac{\sum y_i}{n}  

And we can find the intercept using this:  

b=\bar y -m \bar x  

On this case the correct answer would be:

E.  none of the above

Since the intercept has no association between the increase/decrease of the dependent variable respect to the independent variable

3 0
2 years ago
ASAP... If u scam me :( I will report you :(
RUDIKE [14]
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16) The slope is 0.
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To determine whether x and y have a proportional relationship, see if the line through these points passes through the origin (0, 0).

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5 0
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alukav5142 [94]
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