Answer:
Zero-day exploits
Explanation:
Zero-day exploits refers to recently found vulnerabilities in a computer software program that has been in existence but was hitherto not known and addressed by the software security experts, however, these vulnerabilities were known to hackers. While the existence of these "loop-holes" in the software can go on unnoticed for several years, hackers can take advantage of it to cause harm to the computers' programs and data.
When these attacks occur, it is called a zero-day because the attack took place on the very day that the loop-hole was discovered in the software. So exploitation has already taken place before a fix is carried out.
Answer:
accessing the Paragraph dialog box
Explanation:
Answer:
The solution code is written in C language.
- srand(seedVal);
- printf(" %d \n", rand() % 9);
- printf(" %d \n", rand() % 9);
Explanation:
srand() is a C library function which seeds the random number generator. The srand() function will take one unsigned integer, <em>seedVal</em>, as input parameter (Line 1).
We can print random integer between (and including) 0 and 9 by calculating the random number modulus by 9 (Line 2-3). This will ensure the final random number will also be between 0 and 9.
Answer:
Technically… yes. Because if the charging port is the same as a USB/etc connector port, then it can travel over that.
Explanation:
Answer:
Task 1: T = c + (2.5n(A/M))+ m(1+r/100)ⁿ
Task 2: In both 5 & 10 years, Car A is more economical
Task 3: Printing returns the answer in a different dialogue box while return displays the answer in the same window.
Explanation:
Task 1:
C = Cost of car
n = Number of years
m = Maintenance Cost
r = Rate
M = Mileage per gallon
A = Annual mileage
T= Total Cost
T = c + (2.5n(A/M))+ m(1+r/100)ⁿ
Task 2
Car A In 5 years; T = 20000+ (2.5*5(15000/25))+1300(1+0.15)⁵= $30115
Car B In 5 years; T = 30000+ (2.5*5(15000/32))+1000(1+0.10)⁵= $37470
Therefore in 5 years, Car A is more economical.
Car A In 10 years; T = 20000+ (2.5*10(15000/25))+1300(1+0.15)¹⁰= $40259.225
Car B In 10 years; T = 30000+ (2.5*10(15000/32))+1000(1+0.10)¹⁰= $ 44312.49
Therefore in 10 years, Car A is still economical.
Task 3: Printing returns the answer in a different dialogue box while return displays the answer in the same window.
