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3 years ago

What is the gcf of 14x2 and 4xy

1 answer:

4 0

Hi there! The greatest common factor/divisor (gcf / gcd) is 2x.

We can see this by writing the numbers as multipliers:
$14 {x}^{2} = 7 \times 2 \times x \times x$
$4xy = 2 \times 2 \times x \times y$

Now we can see that the factors which are in common are 2 and x. Therefore the greatest common factor/divisor (gcf / gcd) of the two numbers is 2x.

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Megan and Suzanne each have a plant. They track the growth of their plants for four weeks. Whose plant grew at a faster rate, an

CaHeK987 [17]

In science, rate is a<span> quantity measured with respect to another measured quantity. For the data given, we get the rate of each by calculating the slope. We do as follows:

Megan's rate = 12 - 4.5 / 4 -1 = 2.5 inches per week
Suzanne's rate = 11 - 5 / 4-1 = 0.5 inches per week

Therefore, the plant that grew at a faster rate would be </span><span>Megan’s at 2.5 inches per week.</span>

4 0

2 years ago

Read 2 more answers

What is y<-x+5 and y≤ 2x-1??

olga nikolaevna [1]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

The pair of inequalities is graphed in the attachment.

The first inequality graphs as a shaded area below the dashed line y=-x+5.

The second inequality graphs as a shaded area below the solid line y=2x-1.

The solution set is the doubly-shaded area below the point where the lines intersect.

3 0

3 years ago

What is the distance between P(-4, 3) and Q(6, 1)? Round to the nearest tenth.

seropon [69]

Answer:

10.2

How I found this answer:

4+6=10

3-1=2

10^2+2^2=104

The square root of 104 is 10.1980390272, which can be rounded to 10.2

4 0

3 years ago

Determine the constant of proportionality, k, and interpret it in the context of each problem. 3) The graph shows the relationsh

Aleks04 [339]

I am pretty sure it would be k=50 (pounds) because it goes up 50 each point goes by 50 pounds between each one. (as seen in the edited graph I made)

7 0

2 years ago

Read 2 more answers

What is the solution to the equation 1/x = x+3/2x^2

Dimas [21]

Hello,

As you write 1/x, x must be different of 0.
$\dfrac{1}{x} = \dfrac{x+3}{2x^2} \\

==\textgreater\ 2x^2=x^2+3x \cross`\product \\

==\textgreater\ x^2-3x =0\\

==\textgreater\ x(x-3)=0 \\

==\textgreater\ x=0 (to exclude) or x=3\\

Answer\ x=3
$

8 0

2 years ago

Read 2 more answers