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svlad2 [7]
2 years ago
14

Which one is a better deal?

Mathematics
1 answer:
saul85 [17]2 years ago
5 0
12 pack is a better deal
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Abby has a credit card which uses the adjusted balance method to compute finance charges. Her card has an APR of 11.83%, and she
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The answer to this question is A: 6.08
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3 years ago
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Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. After adding B2 to both sides of the equation in step 4,
Katena32 [7]
2x^2 + 8x - 12 = 0..divide by 2
x^2 + 4x - 6 = 0
x^2 + 4x = 6...add 4 to both sides of the equation
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10....<== ur constant is 10
x + 2 = (+-)sqrt 10
x = -2 (+ - ) sqrt 10

x = -2 + sqrt 10
x = -2 - sqrt 10

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3 years ago
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What is the fifth term in the geometric sequence described by this explicit formula y=40×(-2)^(n-1)​
cupoosta [38]

Answer:

The fifth term is 620

Step-by-step explanation:

y=40×(-2)^(n-1)​

The 5th terms means n=5

y = 40 * (-2) ^ (5-1)

  = 40 * (-2) ^4

  = 40 * (16)

  = 640

5 0
3 years ago
A leading medical journal has claimed that 71% of roller coaster rides get extreme anxiety just before the ride begins. A popula
Anastasy [175]

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2 years ago
Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh
fredd [130]

With

\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k

we have

\mathrm d\vec r=(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

The vector field evaluated over this parameterization is

\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k

so the line integral is

\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

=\displaystyle\int_{-1}^1(16t+6t^2-12t^2)\,\mathrm dt=-4

6 0
3 years ago
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