2x^2 + 8x - 12 = 0..divide by 2
x^2 + 4x - 6 = 0
x^2 + 4x = 6...add 4 to both sides of the equation
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10....<== ur constant is 10
x + 2 = (+-)sqrt 10
x = -2 (+ - ) sqrt 10
x = -2 + sqrt 10
x = -2 - sqrt 10
Answer:
The fifth term is 620
Step-by-step explanation:
y=40×(-2)^(n-1)
The 5th terms means n=5
y = 40 * (-2) ^ (5-1)
= 40 * (-2) ^4
= 40 * (16)
= 640
With

we have

The vector field evaluated over this parameterization is

so the line integral is

