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weqwewe [10]
3 years ago
12

Bluetooth 5 allows data to be transferred between two devices at a rate of

Computers and Technology
2 answers:
iren2701 [21]3 years ago
8 0
Bluetooth 5.0 speed up to 2.0 Mbps

Devices can also communicate over distances of up to 800 feet which is four times the 200 feet allowed by Bluetooth 4.2


Good luck hopefully this helps!!

Lyrx [107]3 years ago
7 0
Yeah your correct because any you connect a Bluetooth to something data transfer
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For this project you will write a Java program that will run a simple math quiz. Your program will generate two random integers
ElenaW [278]

Answer:

Here is the JAVA program:

import java.util.Scanner;   //to accept input from user

public class FunWithBranching {   //class name

   public static void main(String[] args) {  //start of main function

   Scanner input = new Scanner(System.in);  //creates Scanner object

   System.out.print("Enter your name: "); //prompts user to enter name

   String userName = input.nextLine();  //stores the name

   System.out.print("Welcome " + userName + "! Please answer the following questions:\n");   //prompts user to answer the questions

   int randomOperand1 =  (int)(20 * Math.random()) + 1;  //generates random number for operand 1 (1-20)

   int randomOperand2 =  (int)(20 * Math.random()) + 1;  //generates random number for operand 2 (1-20)

   int randomAdd = randomOperand1 + randomOperand2;  //performs addition of two random numbers and stores result in randomAdd

   int randomMul = randomOperand1 * randomOperand2;  //performs multiplication of two random numbers

   int randomDiv = randomOperand1 / randomOperand2;  //performs division of two random numbers

   int randomMod = randomOperand1 % randomOperand2;  //performs modulo of two random numbers

   int correctAns = 0;  //stores number of correct answers

   System.out.print(randomOperand1 + " + " + randomOperand2 + " = ");  //displays random number + random number

   int AdditionGuess = input.nextInt();   //reads the answer of addition from user and stores it in AdditionGuess

   if (AdditionGuess == randomOperand1 + randomOperand2) {  //if the user answer is correct

   System.out.println("Correct!");  //displays correct

   correctAns++;  //adds 1 to the count of correctAns every time the user gives correct answer of addition

 } else {  //if user answer is incorrect

   System.out.println("Wrong!");  //displays wrong

   System.out.println("The correct answer is " + randomAdd);   }  //displays the correct answer of addition

   System.out.print(randomOperand1 + " * " + randomOperand2 + " = ");  //displays random number * random number  

   int MultiplicationGuess = input.nextInt();   //reads the answer of multiplication from user and stores it in MultiplicationGuess

 if (MultiplicationGuess == randomOperand1 * randomOperand2) {  //if the user answer is correct

     System.out.println("Correct!");  //displays correct

     correctAns++;  //adds 1 to the count of correctAns every time the user gives correct answer of multiplication

 }else{  //if user answer is incorrect

       System.out.println("Wrong!");  //displays wrong

       System.out.println("The correct answer is " + randomMul);   }  //displays the correct answer of multiplication

   System.out.print(randomOperand1 + " / " + randomOperand2 + " = ");  //displays random number / random number  

   int DivisionGuess = input.nextInt();   //reads the answer of division from user and stores it in DivisionGuess

   if (DivisionGuess == randomOperand1 / randomOperand2) {  //if the user answer is correct

       System.out.println("Correct!");  //displays correct

       correctAns++;   //adds 1 to the count of correctAns every time the user gives correct answer of division

       }else{  //if user answer is incorrect

           System.out.println("Wrong!");  //displays wrong

           System.out.println("The correct answer is " + randomDiv);     }  //displays the correct answer of division

      System.out.print(randomOperand1 + " % " + randomOperand2 + " = ");  //displays random number % random number  

       int ModGuess = input.nextInt();  //reads the answer of modulo from user and stores it in ModGuess

           if (ModGuess == randomOperand1 % randomOperand2) {  //if the user answer is correct

           System.out.println("Correct!");  //displays correct

           correctAns++;   //adds 1 to the count of correctAns every time the user gives correct answer of modulo

           }else{  //if user answer is incorrect

               System.out.println("Wrong!");  //displays wrong

               System.out.println("The correct answer is " + randomMod);    }  //displays the correct answer of modulo

double percentage = correctAns * 25;   //computes percentage

System.out.println("You got " + correctAns + " correct answers.");   //display number of correct answers given by user

System.out.println("That's " + percentage + "%!");         }  } //displays percentage

Explanation:

The program is well explained in the comments mentioned with each line of code. The screenshot of the output is attached.

3 0
3 years ago
It is okay to use a dust rag when cleaning the inside of a computer.
Sunny_sXe [5.5K]
Yes you can do that, it won't hurt the computer.
4 0
3 years ago
Read 2 more answers
How do computers perform complicated tasks built from simple instructions?
wlad13 [49]
They use and perform a set of actions and programs that build on each other.
8 0
3 years ago
If you want to tune into a radio station that is carried by a signal with wavelength 3.0 meters, what channel would you choose?
Over [174]

Answer:  The radio should be tuned to 100. 0 Mhz.

Explanation:

As radio waves are electromagnetic waves, like x-rays, UV rays, and all the wavelengths of visible light, they propagate in the free space at the speed of light: 3. 10⁸ m/s.

At any wave, there is a fixed relationship between the distance travelled by the wave along one cycle (which is called wavelength ) and the speed at which the wave oscillates (which is called the frequency of the wave), with the speed at which the wave propagates, as follows:

λ (wavelength) =  v (speed) / f (frequency)

Replacing by the values, and solving for frequency, we have:

f = 3. 10⁸ m/seg / 3 m = 10⁸ 1/sec = 10⁸ Hz = 100. 0 Mhz

This is the radio channel to which must be tuned in order to listen the station with a wavelength of 3 m, in the FM band.

6 0
3 years ago
12. In Justify the text is aligned both to the right and to the left margins, adding extra space between words as necessary *
Lena [83]

\blue{

\green{

Answer:

  • False

Explanation:

  • Because, aligment the tex are aligned in the centre of the page.

\pink{

\red{

4 0
3 years ago
Read 2 more answers
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