Answer:
A = 1100cm^2
Step by step Explanation:
given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.
If the width is equal to the length which I assume is true if the width is constant.
than x+30=2x, which means x = 30.
if this is true than 30(30)+200 = 1100cm^2
I added a screenshot with the complete question
Answer:x = 3
y = 9
Explanation:1- getting the value of x:We are given that:
side AB is congruent to side DF. This means that:
AB = DF
3(2x+10) = 12x + 12
6x + 30 = 12x + 12
12x - 6x = 30 - 12
6x = 18
x = 18/6
x = 3
2- getting the value of y:We are given that:
side BC is congruent to side FG. This means that:
BC = FG
2y + 12 = 2(2y-3)
2y + 12 = 4y - 6
4y - 2y = 12 + 6
2y = 18
y = 18/2
y = 9
Hope this helps :)