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3 years ago

Math questions part 2 pls help

Mathematics

1 answer:

ohaa [14]3 years ago

5 0

e in f i think also in i am sorry for calling you names i just get mad when people call me a lier! in i did want to be your friend but you dont want to be my friend in thats fine i just want to let you know i am sorry!

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In a right triangle, one leg is 20 cm and the hypotenuse is 30 cm. To the nearest hundredth of a cm, find the length of the miss

max2010maxim [7]

Answer:

Step-by-step explanation:

Use Pythagoras’ theorem

square of hypotenuse = sum of squares of two other sides

let the missing side be d

30^2 = 20^2 + d^2

600 = 400 + d^2

d^2 = 200

d = square root of 200

d = 14.142 cm

3 0

3 years ago

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Question 7

Pepsi [2]

Answer:

1 : 2.3

Step-by-step explanation

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2 years ago

Zora has bag of potting

Xelga [282]

The question is missing the figure which is attached below.

Answer:

The last box that has dimensions 8 in × 8 in × 10 in

Step-by-step explanation:

Given:

Volume of the soil = 924 cubic inches.

There are four different types of boxes that need to be checked whether they can accommodate all of the soil or not.

The volume of the box must be at least 924 cubic inches to accommodate all of the soil.

Now, volume of the first box is given as:

$V_1=l\times b\times h=20\times 5\times 10=1000\ in^3>924\ in^3$

Volume of the second box is given as:

$V_2=l\times b\times h=10\times 10\times 10=1000\ in^3>924\ in^3$

Volume of the third box is given as:

$V_3=l\times b\times h=10\times 20\times 6=1200\ in^3>924\ in^3$

Volume of the fourth box is given as:

$V_4=l\times b\times h=8\times 8\times 10=640\ in^3$

Therefore, only the volume of the fourth box is less than the total volume of the soil. So, last box is the correct option.

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3 years ago

The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =

avanturin [10]

Given:

The function, f(x) = -2x^2 + x + 5

Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5

The discriminate b^2 - 4ac = 41

To solve for the zeros of the quadratic function, use this formula:

x = ( -b +-√ (b^2 - 4ac) ) / 2a

x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35

Therefore, the zeros of the quadratic equation are 1.85 and -1.35.

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3 years ago

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The area of a square depends on the length of its sides. This can be written in function notation as a(s). What is the best inte

Dominik [7]

Answer:

<em><u>option d is the right answer</u></em>

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2 years ago