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GuDViN [60]
4 years ago
12

Please solve the math question: |4x−4(x+1)|=4

Mathematics
2 answers:
alexgriva [62]4 years ago
3 0

Answer:

x has infinite solutions

Step-by-step explanation:

|4x−4(x+1)|=4

Simplify inside the absolute value by distributing the 4

|4x−4x+4|=4

Combine like terms

|4|=4

The absolute value of 4 is 4

4=4

This is always true, so x is all real values

x has infinite solutions

zlopas [31]4 years ago
3 0

The answer would be 4 = 4

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Solve the equation 14y+82=6x-20 for x if y is 25
Leni [432]

Answer:

x= 226/3 or 75.33333333333333333333333333333

Step-by-step explanation:

14y+82=6x-20

y=25

Sub y=25 into 14y+82=6x-20

14y+82=6x-20

14(25)+82=6x-20

Calculate as follows:

14(25)+82=6x-20

350+82=6x-20

432=6x-20

Add twenty to both sides:

432+20=6x-20+20

452=6x-0

452=6x

Divide both sides by 6

452=6x

452/6=6x/6

452/6=x

x= 226/3 or 75.33333333333333333333333333333

8 0
3 years ago
You have been asked to calculate the break-even point for a new line of souvenir t-shirts. the selling price will be $25 per shi
Klio2033 [76]
200000000000000000000000000000000000000000000000000000000

3 0
3 years ago
The population of a school and is increasing at a rate of 2%per year;6yearsPLEASE HElp <br> Thanks
Shkiper50 [21]

Answer:

It can be modeled with the equation A=P(1.02)^6 but needs a starting population number to finish.

Step-by-step explanation:

To find the population in a future year, use the formula:

A = P (1+/-r)^t

where A is the amount, p is the starting population, r is 2% or 0.02, and t is the number of years.

Since the population is increasing it is addition. Substitute r=0.02 and t=6. Without a starting population, we cannot find the population in 6 years.

A = P (1+r)^t\\A=P(1+0.02)^6\\A=P(1.02)^6


3 0
4 years ago
Which is a way to write 2x2x2x5x5 with exponent and two bases
artcher [175]
Answer: 2^3 * 5^2.
Exclamation: Since 2 is multiplied out three times, you have 2 to the third power. Same goes for the five- since it’s there twice, that’s 5 to the second power. That brings us to 2^3 * 5^2
6 0
2 years ago
Find linear models for each set of data. In what year will the two quantities be​ equal? x y 1970 67.8 1975 69.6 1980 70.5 1985
DaniilM [7]

Answer:

The graph solution is defined in the attachment file please find it.

Step-by-step explanation:

The first line equation:

\to Y= 0.22x + 67.5\\\\

The second line equation:

\to  Y= 0.15x + 75.507\\\\

Intersection points:

\to (114.387,92.665)\\\\

By adding the value of the first year (1970) into the x-value that is

\to 114.387+1970=2084.387

4 0
3 years ago
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