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Ganezh [65]
3 years ago
11

PLEASE HELP!!!!!!!!!!!!!! AND THANK YOU :-) 15 POINTS A concession-stand manager buys bottles of water and soda to sell at a foo

tball game. The manager needs to buy a total of 4,500 drinks and have 25% more water than soda. Let w be the number of bottles of water and let s be the number of bottles of soda. Create a system of equations for w in terms of s that the manager could use to find out how many bottles of water and soda to buy.
(?) = 4500 (?) (?)
W= (?) (?) (?)
Mathematics
2 answers:
babymother [125]3 years ago
7 0

Answer: w+s=4500

w=1.25s

Step-by-step explanation:

Let w be the number of bottles of water and let s be the number of bottles of soda.

Since , the manager needs to buy a total of 4,500 drinks.

Then , we have w+s=4500

Also, the they have 25% more water than soda.

Since 25%=0.25

Then, w=s+0.25s=s(1.25)

\Rightarrow\ w=1.25s

Hence, the  system of equations for w in terms of s that the manager could use to find out how many bottles of water and soda to buy.

w+s=4500

w=1.25s

3241004551 [841]3 years ago
4 0
The manager needs to buy 3375 water bottles and 1125 sodas and both will equal 4500. hope this helps

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Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

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Hence final answer is

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6 0
3 years ago
I will give lots of points please help
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Answer:

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b)  27  in³

c)  divide the volume of the slice of cake by the volume of the whole cake

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Step-by-step explanation:

<h3><u>Part (a)</u></h3>

The cake can be modeled as a <u>cylinder </u>with:

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<h3><u>Part (b)</u></h3>

\begin{aligned}\textsf{Circumference of the cake} & = \sf \pi d\\& = \sf 9 \pi \:\:in\end{aligned}

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\begin{aligned}\implies \textsf{Volume of slice of cake} & = \sf \dfrac{3}{9 \pi} \times \textsf{volume of cake}\\\\& = \sf \dfrac{3}{9 \pi} \times 81 \pi\\\\& = \sf \dfrac{243 \pi}{9 \pi}\\\\& = \sf 27\:\:in^3\end{aligned}

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If the four slices of cake are cut and passed out <em>before </em>anyone eats or looks for the marble, the probability of getting the marble is the same for everyone. If one slice of cake is cut and checked for the marble before the next slice is cut, the probability will increase as the volume of the entire cake decreases, <u>until the marble is found</u>.  So it depends upon how the cake is cut and distributed as to whether Hattie's strategy makes sense.

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he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

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Step-by-step explanation:

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