Question

PLEASE HELP!!!!!!!!!!!!!! AND THANK YOU :-) 15 POINTS A concession-stand manager buys bottles of water and soda to sell at a football game. The manager needs to buy a total of 4,500 drinks and have 25% more water than soda. Let w be the number of bottles of water and let s be the number of bottles of soda. Create a system of equations for w in terms of s that the manager could use to find out how many bottles of water and soda to buy.
(?) = 4500 (?) (?)
W= (?) (?) (?)

Answer 1

Answer: $w+s=4500$

$w=1.25s$

Step-by-step explanation:

Let w be the number of bottles of water and let s be the number of bottles of soda.

Since , the manager needs to buy a total of 4,500 drinks.

Then , we have $w+s=4500$

Also, the they have 25% more water than soda.

Since 25%=0.25

Then, $w=s+0.25s=s(1.25)$

$\Rightarrow\ w=1.25s$

Hence, the  system of equations for w in terms of s that the manager could use to find out how many bottles of water and soda to buy.

$w+s=4500$

$w=1.25s$

Answer 2

The manager needs to buy 3375 water bottles and 1125 sodas and both will equal 4500. hope this helps