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strojnjashka [21]
2 years ago
11

Lots of Points, Help. EXPLAIN HOW!

Mathematics
2 answers:
tekilochka [14]2 years ago
5 0

Answer:

y+7 < -7   <u>OR</u>    y+7 > 7   (No correct option in your question)

Step-by-step explanation:

3|y + 7| − 16 > 5

3|y + 7| − 16 +16> 5+16

3|y + 7|>21

3|y + 7| / 3 > 21 /3

|y + 7| > 7

+(y+7) > 7        OR      -(y+7) > 7

y+7>7   OR    y+7 < -7

almond37 [142]2 years ago
4 0

Answer:

Introduction to Inequalities

Introduction to InequalitiesInequalities are used to demonstrate relationships between numbers or expressions.

Introduction to InequalitiesInequalities are used to demonstrate relationships between numbers or expressions.

LEARNING OBJECTIVES

Introduction to InequalitiesInequalities are used to demonstrate relationships between numbers or expressions.

LEARNING OBJECTIVES

Explain what inequalities represent and how they are used

Introduction to InequalitiesInequalities are used to demonstrate relationships between numbers or expressions.

LEARNING OBJECTIVES

Explain what inequalities represent and how they are used.

KEY TAKEAWAYS

Introduction to InequalitiesInequalities are used to demonstrate relationships between numbers or expressions.

LEARNING OBJECTIVES

Explain what inequalities represent and how they are used

TAKEAWAYS Key Points

Inequalities are particularly useful for solving problems involving minimum or maximum possible values.

Inequalities are particularly useful for solving problems involving minimum or maximum possible values.Key Terms

Inequalities are particularly useful for solving problems involving minimum or maximum possible values.Key Termsnumber line: A visual representation of the set of real numbers as a series of points.

Inequalities are particularly useful for solving problems involving minimum or maximum possible values.Key Termsnumber line: A visual representation of the set of real numbers as a series of points.inequality: A statement that of two quantities one is specifically less than or greater than another.

Step-by-step explanation:

In mathematics, inequalities are used to compare the relative size of values. They can be used to compare integers, variables, and various other algebraic expressions. A description of different types of inequalities follows.

Hope it helps you

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riadik2000 [5.3K]
2x + 3 = 9      Move all terms not containing x to the right side of the equation.

2x = 6             Divide each term by 2 and simplify.

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aleksklad [387]

Answer:

x = 17

Step-by-step explanation:

8x - 9 + 53 = 180 (collect like terms)

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3 years ago
Directions: Complete all 3 questions. Make sure you include a graph, work and conclusion.
Simora [160]

Prove that the quadrilateral whose vertices are I(-2,3), J(2,6), K(7,6), and L(3, 3) is a rhombus.

I think in these problems the first step is to express each side as a vector.  A vector is the difference between points.  When two sides have the same vector (or negatives) it means they're parallel and congruent.  So in a rhombus IJKL the vectors IJ and LK should be the same, as should JK and IL.  That much assures a parallelogram; we check IJ and JK are congruent to complete the crowing of the rhombus.

Let's calculate these vectors:

IJ = J - I = (2,6) - (-2,3) = (2 - -2, 6 - 3) = (4, 3)

LK = K - L = (7, 6) - (3, 3) = (4, 3)

IJ = LK, so far so good

(Note: If you haven't got to vectors yet you can just show the two sides are the same length, 5, and have the same slope, 3/4, both of which can be read off the vectors.)

JK = K - J = (7,6) - (2,6) = (5,0)

IL = L - I = (3, 3) - (-2, 3)  = (5, 0)

Those are the same too.    

Now we have to show IJ ≅ JK

The length of IJ is the cliche √4²+3² = 5, the same as JK, so IJ ≅ JK

We showed all four sides are congruent and we have two pair of parallel sides, so we have a rhombus.

8 0
3 years ago
Pls help Im very stuck on this and don’t understand
Lady bird [3.3K]

Answer:

C. 85 degrees

Step-by-step explanation:

Step 1: Set up equation

x + 57 + 96 + x = 131

Step 2: Solve for <em>x</em>

2x + 153 = 131

2x = -22

x = -11

Step 3: Find m∠RQU

m∠RQU = 96 + <em>x</em>

m∠RQU = 96 - 11

m∠RQU = 85°

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