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3 years ago

Drag and drop each number to its correct position on the number line.

Mathematics

2 answers:

AnnZ [28]3 years ago

7 0

Hello!

It might be a bit sloppy, but I got a picture, from left to right, I labeled each 1-4.
{photo}

Hope this helps! ☺♥

AnnZ [28]3 years ago

6 0

Hello
i did this answer recently and i attached an image of what it is.

You might be interested in

Click on the words to go to the picture

melisa1 [442]

I think answer is B.I am not sure because I found purple it is 1.350 but I found the yellow is 240 and it is more close to 420.I telling you I am not sure but this is my opininon.

5 0

3 years ago

Read 2 more answers

A tank contains 100 gal of water and 50 oz of salt. Water containing a salt concentration of ¼ (1 + ½ sin t) oz/gal flows ito th

Likurg_2 [28]

Answer:

Part a)

$y\left(t\right)=\frac{-1250cost+25sint}{5002}+25+\frac{63150}{2501}\frac{1}{e^{\frac{t}{50}}}$

Part b)

Check the attached figure to see the ultimate behavior of the graph.

Part c)

The level = 25, Amplitude = 0.2499

Step-by-step Solution:

Part a)

Given:

$Q(0)=50$

Rate in:

$\frac{1}{4}\left(1+\frac{1}{2}sint\right)\cdot 2\:=\:\frac{1}{2}\left(1+\frac{1}{2}sint\right)$

Rate out:

$\frac{Q}{100}\cdot 2=\frac{Q}{50}$

So, the differential equation would become:

$\frac{dQ}{dt}=\frac{1}{2}\left(1+\frac{1}{2}sint\right)-\frac{Q}{50}$

Rewriting the equation:

$\frac{dQ}{dt}+\frac{Q}{50}=\frac{1}{2}\left(1+\frac{1}{2}sint\right)$

As $p(x)$ is the coefficient of $y$ , while $q(x)$ is the constant term in the right side of the equation:

$p\left(x\right)=\frac{1}{50}$

$q\left(x\right)=\frac{1}{2}\left(1+\frac{1}{2}sint\right)$

First it is important to determine the function $\mu$ :

$\mu \left(t\right)=e^{\int \:p\left(t\right)dt}$

$=e^{\int \:\left(\frac{1}{50}\right)dt}$

$=e^{\frac{t}{50}}$

The general solution then would become:

$y\left(t\right)=\frac{1}{\mu \left(t\right)}\left(\int \mu \left(t\right)q\left(t\right)dt+c\:\right)$

$=\frac{1}{e^{\frac{t}{50}}}\int e^{\frac{t}{50}}\:\frac{1}{2}\left(1+\frac{1}{2}sint\right)dt+\frac{1}{e^{\frac{t}{50}}}c$

$=\frac{1}{e^{\frac{t}{50}}}\left(\frac{-25e^{\frac{t}{50}}\left(50cost-sint\right)}{5002}+25e^{\frac{t}{50}}\right)+\frac{1}{e^{\frac{t}{50}}}c$

$=\frac{\left-1250cost+25sint\right}{5002}+25+\frac{1}{e^{\frac{t}{50}}}c$

Evaluate at $t=0$

$50=y\left(0\right)=\frac{\left(-1250cos0+25sin0\right)}{5002}+25+\frac{1}{e^{\frac{0}{50}}}c$

Solve to c:

$c=25+\frac{1250}{5002}$

$\mathrm{Cancel\:}\frac{1250}{5002}:\quad \frac{625}{2501}$

$c=25+\frac{625}{2501}$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:25=\frac{25\cdot \:2501}{2501}$

$c=\frac{25\cdot \:2501}{2501}+\frac{625}{2501}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$c=\frac{25\cdot \:2501+625}{2501}$

$c=\frac{63150}{2501}$

$c\approx 25.25$

Therefore, the general solution then would become:

$y\left(t\right)=\frac{-1250cost+25sint}{5002}+25+\frac{63150}{2501}\frac{1}{e^{\frac{t}{50}}}$

Part b) Plot the Solution to see the ultimate behavior of the graph

The graph appears to level off at about the value of $Q=25$ .

The graph is attached below.

Part c)

In the graph we note that the level is $Q=25$ .

Therefore, the level = 25

The amplitude is the (absolute value of the) coefficient of $cost\:t$ in the general solution (as the coefficient of the sine part is a lot smaller):

Therefore,

$A=\frac{1250}{5002}\:\approx 2.499$

Keywords: differential equation, word problem

Learn more about differential equation word problem from brainly.com/question/14614696

#learnwithBrainly

4 0

3 years ago

Divide.

Llana [10]

$Hello$ $There!$

The answer is...

$-\frac{20}{27} .$

Hopefully, this helps you!!

If you need a explanation just comment my questions. :)

$AnimeVines$

7 0

3 years ago

Problem: Jeanie has 3/4 yard piece of ribbon. She needs one 3/8 yard piece and one 1/2 yard piece. Can she cut the piece of ribb

Debora [2.8K]

No she can not. She has 3/4 or 6/8 subtract the 3/8 and she has 3/8. Now she needs 1/2 or 4/8 she can not get it because 4/8>3/8.

8 0

4 years ago

The blue whale is the largest animal living on the earth. The average blue whale measures 100 feet long (30 meters) and weighs 3

dangina [55]

Whales head : 1/3(100) = 100/3 = 33.33 ft or 1/3(30) = 30/3 = 10 meters
new baby whale : 1/4(100) = 100/4 = 25 ft. or 1/4(30) = 30/4 = 7.5 meters
average man height : 1/17(100) = 100/17 = 5.88 ft or 1/17(30) = 30/17 = 1.76 m
average man weight : 1/1818(300000) = 300000/1818 = 165 lbs or 1/1818(136000) = 136000/1818 = 74.81 kilograms
human baby height : 1/4(5.88) = 5.88/4 = 1.47 ft or 1/4(1.76) = 0.44 meters

4 0

3 years ago