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lyudmila [28]
3 years ago
10

Find all solutions to the equation. 2sin theta - squareroot 3 = 0

Mathematics
1 answer:
Xelga [282]3 years ago
8 0

Answer:

\theta =2mπ + π/3 for m ∈ Z.

Step-by-step explanation:

Given the equation 2sin\theta - \sqrt{3} = 0, we are to find all the values of \theta that satisfies the equation.

2sin\theta - \sqrt{3} = 0\\\\2sin\theta = \sqrt{3} \\\\sin\theta = \sqrt{3}/2 \\\\\theta = sin{-1} \sqrt{3}/2 \\\\\theta = 60^0

General solution for sin\theta is \theta = nπ + (-1)ⁿ ∝, where n ∈ Z.

If n is an even number say 2m, then \theta = (2m)π + ∝ where ∝ = 60° = π/3

Hence, the general solution to the equation will be \theta = 2mπ + π/3 for m ∈ Z.

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